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3 years ago

11

A big contains 2.45 liters of cranberry juice. A bottle contains 2 13/25 liters of grape juice. Which container holds less fruit

juice? How much less?

1 answer:

liubo4ka [24]3 years ago

6 0

The jug holds 0.07 liters less than the bottle.

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Please help with ALEKS >-< ..................................

andrey2020 [161]

Answer:

4.5

Step-by-step explanation:

From the file, we see that;

Horizontal distance from bottom of ladder to side of house = 2

Length of ladder leaning against side of the house = 4 m.

Now we want to find the distance from the top of the ladder to the ground which we can call d.

Thus we can find it from pythagoras theorem.

d = √(2² + 4²)

d = √(4 + 16)

d = √20

d = 4.47

To the nearest tenth gives;

d = 4.5

5 0

3 years ago

The diameter of the base of a water bottle is 3 1/2 inches. What is the length on inches of the diameter of 6 of these water bot

olga_2 [115]

Answer:

21

Step-by-step explanation:

3.5 x 6 = ?

3 0

2 years ago

A group of eight grade 11 and five grade 12 students wish to be on the senior prom committee. The committee will consist of thre

BaLLatris [955]

5/13*4/12*3/11=5/143 I believe

7 0

3 years ago

Recall the equation that modeled the volume of the raised flower bed, y, in terms of the width of the box, y = x3 + 11x2 − 312x.

Julli [10]

Answer:

x = 17.349

Step-by-step explanation:

The right-most x-intercept is 17.349, where the curve continues upward to the right.

4 0

3 years ago

which of the three sets could not be the lengths of the sides of a triangle {6,10,12} {5,7,10} {4,4,9} {2,3,3}

Phoenix [80]

So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

$A+B>C\\A+C>B\\B+C>A$

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

$6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}$

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

$5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}$

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

$4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}$

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

$2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}$

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

5 0

3 years ago

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