All categories

4 years ago

Subtract 8-4 1/2. A. 3 B. 4 C. 4 1/2 D. 3 1/2

Mathematics

1 answer:

kicyunya [14]4 years ago

3 0

This was the answer I came up with - 3.5

You might be interested in

A sphere has a diameter of 24 units. What is its volume in cubic units?

horrorfan [7]

The volume of a sphere is a 3/4 pi r^2 so we know the radius is 12 so 12 square is 144 pi 144*3=432 /4=108. volume is 108 pi cubed units

7 0

3 years ago

Using technology or by hand, make a dot plot representing the data shown in the table. Make sure to label your plot appropriatel

Alchen [17]

Second one should be wright 86%

5 0

3 years ago

What is the correct answer?

Scorpion4ik [409]

Answer:

yellow

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.

hichkok12 [17]

Answer:

$2\pi(e^2-e^{-4})$

Step-by-step explanation:

We are given: $f(x)=2e^x$

So, the integral will be used to calculate the volume.

$V = \pi\int\limits^1_{-2}(2e^x)^2dx=\pi\int\limits^1_{-2}4e^{2x}dx=2\pi e^{2x}|^1_{-2} =2\pi(e^2-e^{-4})$

5 0

4 years ago

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

2 years ago