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hjlf
3 years ago
14

Wrong Answer I report You And You Don't Get Your Points

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

1. Joe- 2+b (or 2+1b)

   Micheal- 2b

2. Joe- 2+10=12

   Micheal- 2x10=20

3. one distributes and the other just adds regularly.

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How to work vector algebra
erica [24]

Vectors and vector addition:

A scalar is a quantity like mass or temperature that only has a magnitude. On the other had, a vector is a mathematical object that has magnitude and direction. A line of given length and pointing along a given direction, such as an arrow, is the typical representation of a vector. Typical notation to designate a vector is a boldfaced character, a character with and arrow on it, or a character with a line under it (i.e., ). The magnitude of a vector is its length and is normally denoted by or A.  Addition of two vectors is accomplished by laying the vectors head to tail in sequence to create a triangle such as is shown in the figure.  The following rules apply in vector algebra.where P and Q are vectors and a is a scalar. 

Unit vectors:

A unit vector is a vector of unit length. A unit vector is sometimes denoted by replacing the arrow on a vector with a "^" or just adding a "^" on a boldfaced character (i.e., ). Therefore, Any vector can be made into a unit vector by dividing it by its length. Any vector can be fully represented by providing its magnitude and a unit vector along its direction.

Base vectors and vector components:

Base vectors are a set of vectors selected as a base to represent all other vectors. The idea is to construct each vector from the addition of vectors along the base directions. For example, the vector in the figure can be written as the sum of the three vectors u1, u2, and u3, each along the direction of one of the base vectors e1, e2, and e3, so that Each one of the vectors u1, u2, and u3 is parallel to one of the base vectors and can be written as scalar multiple of that base. Let u1, u2, and u3 denote these scalar multipliers such that one has<span> </span><span>The original vector</span><span> </span><span>u</span><span> </span><span>can now be written as </span><span>The scalar multipliers</span><span> </span><span>u</span><span>1</span><span>,</span><span> </span><span>u</span><span>2</span><span>, and</span><span> </span><span>u</span><span>3</span><span> </span><span>are known as the components of</span><span> </span><span>u</span><span> </span><span>in the base described by the base vectors</span><span> </span><span>e</span><span>1</span><span>,</span><span> </span><span>e</span><span>2</span><span>, and</span><span> </span><span>e</span><span>3</span><span>. If the base vectors are unit vectors, then the components represent the lengths, respectively, of the three vectors</span><span> </span><span>u</span><span>1</span><span>,</span><span> </span><span>u</span><span>2</span><span>, and</span><span> </span><span>u</span><span>3</span><span>. If the base vectors are unit vectors and are mutually orthogonal, then the base is known as an orthonormal, Euclidean, or Cartesian base.</span>

 

A vector can be resolved along any two directions in a plane containing it. The figure shows how the parallelogram rule is used to construct vectors a and b that add up to c. <span>In three dimensions, a vector can be resolved along any three non-coplanar lines. The figure shows how a vector can be resolved along the three directions by first finding a vector in the plane of two of the directions and then resolving this new vector along the two directions in the plane. </span><span>When vectors are represented in terms of base vectors and components, addition of two vectors results in the addition of the components of the vectors.</span>

8 0
3 years ago
Read 2 more answers
What is the exact volume of a sphere that has a radius of 18 m?
krok68 [10]

Answer:

36

Step-by-step explanation:

36 u think you need to multiply it by 2

7 0
3 years ago
The function f(x) = x is translated such that the function describing the translated graph is g(x) = (x + 5)' + 2. Where
Tresset [83]

Answer:

  (-5, 2)

Step-by-step explanation:

  g(x) = f(x -h) +k

is a translation of f(x) h units to the right and k units upward. Here, we seem to have h=-5 and k=2. That means the point (0, 0) has been translated 5 units to the left (to -5) and 2 units upward (to 2).

The translated location of (0, 0) is (-5, 2).

_____

We assume we're to ignore the apostrophe (') in the equation for g(x).

8 0
3 years ago
Which of the following is the graph of y=sqr root -x-3
Elan Coil [88]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

y=\sqrt{-x-3}

we know that

The radicand must be greater than or equal to zero

so

(-x-3)\geq 0

solve for x

Adds 3 both sides

-x\geq 0+3

-x\geq 3

Multiply by -1 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

x\leq -3

so

The domain of the function is the interval (-∞,-3]

For x=-3 ---> the value of y=0

The range is the interval {0,∞)

therefore

The graph in the attached figure

3 0
3 years ago
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
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