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nirvana33 [79]
3 years ago
8

A jewellery shop sells 240 necklaces in a month. 180 were sold via the shops website, the rest were sold in a high street shop.

work out the ratio for online sales to shop sales
Mathematics
1 answer:
lina2011 [118]3 years ago
3 0
3:4

aaaaaaaaaaaaaaaaaaaaaa
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110% of 90 is what number a ?<br><br>? = 110 over 100<br>please help​
densk [106]

Answer:

90 is the orrect answer because I said so

Step-by-step explanation:

3 0
3 years ago
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If you worked for 6 days for a total of 67.8 hours. If I worked the same number of hours each day, how many hours did I work in
Hunter-Best [27]
Hi there!

To solve this problem, we need to divide 67.8 by 6 to find the amount of hours each day. 

67.8 / 6 = 11.3

You worked 11.3 hours each day. 

Hope this helps!
8 0
3 years ago
What is the volume of the figure below, which is composed of two cubes with side lengths of 9 units?
ivann1987 [24]

Answer:

C. 1458 cubic units

Step-by-step explanation:

one cubes side length is 9. The only side that changes is the length since the size is doubled so instead of it 9 it would be 18.

V= L × W × H

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= 1,458

hope this helped youuu

8 0
3 years ago
What’s the answer please help
noname [10]

Answer:

\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}

3 0
3 years ago
Checking my work. which one?
Genrish500 [490]

Answer:

Dividing exponents you subtract.

3^8/3^5 = 3^3

3^3

Multiplying exponents when an exponent is raised to another.

(3^3)^3 = <u>3^9</u>

<h2>Final Answer is 3^{9}</h2><h2 />

Apparently this makes no sense according to comments, if you want a more indepth look into exponents search "The properties of exponents".

6 0
3 years ago
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