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nirvana33 [79]
3 years ago
8

A jewellery shop sells 240 necklaces in a month. 180 were sold via the shops website, the rest were sold in a high street shop.

work out the ratio for online sales to shop sales
Mathematics
1 answer:
lina2011 [118]3 years ago
3 0
3:4

aaaaaaaaaaaaaaaaaaaaaa
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c) 75%

Step-by-step explanation:

We are given the following information in the question:

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Standard Deviation, σ = 15 days

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z_{score} = \displaystyle\frac{x-\mu}{\sigma}

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P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

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Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

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