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Svetach [21]
3 years ago
9

Leslie went out for a jog. When she returned she went to the tap and filled up her 500 mL reusable water bottle. She drank 250 m

L at a constant rate in one minute. Her phone rang, she set down the bottle of water and talked to her friend for four minutes. After her phone call she sipped the rest of her bottle at a constant rate in two minutes. Create a voulme vs. time graph for this story.

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

Please find attached the required graph and

Step-by-step explanation:

The values for the information given can be written down as follows;

Time, seconds             Volume mL

0,                                    500

12,                                   450

24,                                  400

36,                                  350

48,                                  300

60,                                  250

72 250

84 250

96 250

108 250

120 250

132 250

144 250

156 250

168 250

180 250

192 250

204 250

216 250

228 250

240 250

252 250

264 250

276 250

288 250

300 250

312 225

324,                                        200

336,                                         175

348,                                         150

360,                                         125

372,                                         100

384,                                         75

396,                                        50

408,                                        25

420,                                        0

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B.  \:  \boxed{66.8}

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to \: solve \: this \: little \: poblem : we \:apply \: the \: pythagrean \: rule \to \\  \boxed{SOH} \boxed{CAH} \boxed{TOA} \to \\ we \: are \: been \: given :  \to \\ the \:  \boxed{opp }\: of \: the \: required \: angle \:  = 35. \\ the \:  \boxed{adj }\: of \: the \: required \: angle \:  = 15. \\  now \: lets \: apply \: \boxed{TOA}\to \: \tan( \theta)  =  \frac{opp}{adj}   \to\\  \tan( \theta)  =  \frac{opp}{adj}  =  \frac{35}{15}  = 2.3333333333 \\  \theta =  \tan {}^{ - 1} (2.3333333333)  \\   \boxed{\theta = 66.80}

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