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4 years ago

Please help and explain please !!!!!!

Mathematics

2 answers:

Vaselesa [24]4 years ago

5 0

21. 2•2=4
24. 3.4•2.4=5.8
27. -1.6•3.6=-5.76
30. 3/1.4=2.1

Hope this helps!

rewona [7]4 years ago

4 0

These are square root problems.
if you have a scientific calculator,then use it in the future, because it helps.
1. sqrt of 4=2X2=4.
2. the sqrt of 12 and 6 is a long decimal, so it is shortened. 3.46X2.44=8.4424
3. 2.64-1 =1.64
4. 3/1.41=2.12
Hope this helps!

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Step-by-step explanation:

you cannot just put the actual numbers in and calculate ?

and you can't provide the correct problem statement, as it seems.

I assume you mean

an = 3n² - 1

a sequence starts with a1, so, n>=1

a1 = 3×1² - 1 = 3-1 = 2

a2 = 3×2² -1 = 3×4 - 1 = 12 - 1 = 11

a3 = 3×3² - 1 = 3×9 - 1 = 27 - 1 = 26

a4 = 3×4² - 1 = 3×16 - 1 = 48 - 1 = 47

a5 = 3×5² - 1 = 3×25 - 1 = 75 - 1 = 74

there, that is all there is to it. you really needed help with that ?

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Answer:

1) 4, -5 and 3 are the ZEROES of the expression j = (p - 4)(p + 5)(p - 3)

Step-by-step explanation:

Here, the given phrase is:

j = (p - 4)(p + 5)(p - 3)

Now, here j is Expressed as the product of roots.

(p - 4),(p + 5) and (p - 3) are 3 given roots of the polynomial j.

Now, if (x-a) is the ROOT of the polynomial, then x = a is the ZERO of the POLYNOMIAL.

In this given expression:

(p-4) is the ROOT⇒ 4 is the ZERO of the polynomial j.

(p+5) is the ROOT⇒ (-5) is the ZERO of the polynomial j.

(p-3) is the ROOT⇒ 3 is the ZERO of the polynomial j.

Hence, here 4, -5 and 3 are the ZEROES of the expression

j = (p - 4)(p + 5)(p - 3)

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