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3 years ago

Given that 5(x+k)=4x = 20 and that x is positive show that k < 4

Mathematics

1 answer:

Butoxors [25]3 years ago

7 0

One of these is possibly the answer to your question:

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Please answer correctly !!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!

Naddik [55]

X=7
10x-2=9x+5
X=7
Lol it says I need more characters to submit this

8 0

3 years ago

Can someone please help me?

Ivahew [28]

Im guessing either 2/3*570 or 1/3*5700

4 0

3 years ago

Read 2 more answers

Find the 9th term of the geometric sequence 9, 27, 81,

amm1812

Answer:

You have to multiply the last number by 3. So 9 times 3 equals 27 and 27 times 3 equals 81 and so on. The answer would be 59,049

Step-by-step explanation:

I hope this helps!!

5 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago

in a game involving a pair of fair dice a player rolls the dice until he gets a sum of 7 let z equal the number of rolls it take

Anarel [89]

Answer:

z = 36 rolls , probability for getting 7 = 1/6

Step-by-step explanation:

A die has 6 possible outcomes, which sums to 36 for two dice for every value on both dice.

The outcomes for rolling both dice for 36 times gives 6 possible outcomes summing to 7, that is, (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

There the probability of getting a sum dice of 7 is:

= 6 / 36 = 1/6

8 0

3 years ago