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3 years ago

Find the 9th term of the geometric sequence 9, 27, 81,

Mathematics

1 answer:

amm18123 years ago

5 0

Answer:

You have to multiply the last number by 3. So 9 times 3 equals 27 and 27 times 3 equals 81 and so on. The answer would be 59,049

Step-by-step explanation:

I hope this helps!!

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What was haley’s function in standard form

Stels [109]

Answer: 7,-10,-2

Step-by-step explanation:

3 0

3 years ago

Complete the remainder of the<br> table for the given function rule:

melamori03 [73]

Answer:

-3=2

0=0

3=-2

6=-4

3 0

3 years ago

Graph the linear inequality: 2x + 3y = 12, by creating a t-chart to plot the points. Shade by

Crazy boy [7]

Answer:

See explanation

Step-by-step explanation:

Assuming the given inequality is $2x+3y\le12$

Then the corresponding linear equation is $2x+3y=12$

When x=0, we have $2*0+3y=12$

$\implies 3y=12\implies y=4$

When y=0, we have $2x+3*0=12$

$\implies 2x=12\implies x=6$

The T-table is:

0 | 4

6 | 12

We plot this points and draw a solid straight line as shown in the attachment.

Now let us test the origin: (0,0) by plugging x=0 and y=0 into the inequality.

$2*0+3*0\le12$

$0\le12$ ....This is true so we shade the lower half plane as shown in the attachment.

6 0

3 years ago

Sal and her three friends plan to bowl one or two games each. Each game costs $2.50 each. Identify the independent and dependent

tino4ka555 [31]

So the dependent is the number of games because it's not definite they dont know for sure. so the domain always involves money!!! always! the range wiyld be the numbers they migh play like 8-10 so 4 to 8 is the range value. so determining off of that the indepedent variable would be the total cost becuase it wont change so your answer is C hope this helped have a good day!!!

3 0

3 years ago

Read 2 more answers

Someone please help me??

lapo4ka [179]

The standard equation of a circle with centre (xc,yc) and radius R is given by

$(x-x_c)^2+(y-y_c)^2=R^2$

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore

$(x-x_c)^2+(y-y_c)^2=R^2$
$(x-4)^2+(y-(-3))^2=2.5^2$
$(x-4)^2+(y+3)^2=2.5^2$ or
(x-4)^2+(y+3)^2=6.25

7 0

3 years ago