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3 years ago

Identify the linear term in the function

Mathematics

1 answer:

AveGali [126]3 years ago

4 0

Answer:

-5x

Step-by-step explanation:

The linear term is the term with the variable to the first power. Here, it is -5x.

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<em>Comment on other terms</em>

2x^2 has x to the 2nd power

-12 has x to the 0 power (no variable)

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Plz Work out -1x(6x-8)=

Andrew [12]

-1x(6x - 8)

= -x(6x - 8)

= -x(6x) - x(-8)

= -6x^2 + 8x

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3 years ago

-3/12 - -2/3 can you please help me

MatroZZZ [7]

Answer:

5 /12

Step-by-step explanation:

8 0

4 years ago

Thi sis the question

jek_recluse [69]

$\text{Given that,}\\\\x^2 + \dfrac1{x^2} = 38\\\\\\(i)\\\\\left(x-\dfrac 1x \right)^2 = x^2 + \dfrac 1{x^2} - 2 \cdot x \cdot \dfrac 1x\\\\\\\implies \left(x-\dfrac 1x \right)^2 = 38 -2 = 36\\\\\implies x - \dfrac 1x = \pm\sqrt{36} = \pm 6 \\\\\\(ii)\\\\x^2 + \dfrac 1{x^2} = 38\\\\\\\implies \left(x^2 + \dfrac 1{x^2} \right)^2 = 38^2\\\\\\\implies x^4 + \dfrac 1{x^4} + 2\cdot x^2 \cdot \dfrac 1{x^2} = 1444\\\\\\\implies x^4 + \dfrac 1{x^4} + 2 = 1444\\\\\\$

$\implies x^4 +\dfrac 1{x^4} = 1444-2 = 1442$

7 0

2 years ago

Hello plz help I have 5 F’s

brilliants [131]

I can understand why it might be tough, so I'm here to help.

Translation is as simple as moving the points as told.

For example, do you see where point T currently resides? From there you'd move it 4 units to the left and 5 down, where it'd end up at (-4,-3). Now do the same for every point.

Point T would end up at (-4,-3)

Point S would end up at (-2,-2)

Point R would end up at (0,-3)

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3 years ago

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goblinko [34]

Answer:

1,1

2,2

3,3

4,4

5,5

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3 years ago

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