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aliya0001 [1]
3 years ago
13

Joshua is putting in a new circular shaped fire pit in his backyard. The diameter of the fire pit is 4 feet. What area of the ba

ckyard does the fire pit cover?
Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

A≈12.57ft²

This is the answer ^

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WILL MARK BRAINLIEST!!!
wariber [46]

f(x) = -9x^4 + 5x + 3\\\\ f(-x)= -9(-x)^4 + 5\cdot(-x) + 3=-9x^4-5x+3\\\\ f(-x)\not =f(x)\implies \text{ not even}\\\\ -f(x)=-( -9x^4 + 5x + 3)= 9x^4 - 5x - 3\\\\ -f(x)\not =f(-x) \implies \text{ not odd}

Neither

4 0
2 years ago
1. Bob tried to answer the following question by finding the missing angle and rounding the answer to the nearest degree.
iren2701 [21]

Answer:

Part 1)

Bob's mistake was to have used the cosine instead of the sine

The measure of the missing angle is 53.13\°

Part 2) The surface area of the pyramid is 288\ cm^{2}

Step-by-step explanation:

Part 1)

Let

x----> the missing angle

we know that

In the right triangle o the figure

The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle

sin(x)=\frac{16}{20}

x=arcsin(\frac{16}{20})=53.13\°

Bob's mistake was to have used the cosine instead of the sine

Part 2) we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^{2}+4[\frac{1}{2}(b)(h)]

where

b is the length side of the square

h is the height of the triangular lateral face

In this problem

h=b/2 -------> by an 45° angle

so

b=2h

sin(45\°)=\frac{h}{6\sqrt{2}}

h=6\sqrt{2}(sin(45\°))=6\ cm

Find the value of b

b=2(6)=12\ cm

Find the surface area

SA=12^{2}+4[\frac{1}{2}(12)(6)]=288\ cm^{2}

3 0
3 years ago
The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
SCORPION-xisa [38]

Answer:

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: \mu \leq 15

Alternative hypothesis: \mu > 15

And the statistic is given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

7 0
3 years ago
The value of <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D" id="TexFormula1" title="\sqrt[3]{x}" alt="\sqrt[3]{x}" ali
Alexandra [31]

 

\displaystyle\\6

.

5 0
3 years ago
Read 2 more answers
Please help ❤️❤️❤️❤️
Mekhanik [1.2K]
The answer isw c because when i first looked at it i was like its a then i soveled the problem out
7 0
3 years ago
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