IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
Answer: 20x + 20
Step-by-step explanation: In this problem, the 5 "distributes" through the parentheses, multiplying by each of the terms inside.
So we have 5(4x) + 5(4) which simplifies to 20x + 20.
Answer:
y^2/x^6
apply exponent rule:
x^-2/x^4=1/x^4-(-2)=y/y^-1 x^4 -(-2)
then you subtract 4-(-2)=6
y/x^6 y^-1
cancel out the common factor: y^-1 and you get
y^2
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x^6
Answer:a
Step-by-step explanation:
