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guapka [62]
3 years ago
10

I don’t know the answer

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

Answer:

3 is the answer

Step-by-step explanation:

Mark brainliest

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Enter expression, e.g. (x^2-y^2)/(x-y)
Drupady [299]
The answer i got was x+y
5 0
3 years ago
What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t
agasfer [191]

Answer:

  \boxed{90}\,\text{units$^2$}

Step-by-step explanation:

The sides AB and CD are parallel to the x-axis and 5 units apart. The length of side AB is 6-(-12) = 18 units. The area is the product of these dimensions:

  Area = (Base)(Height) = (18 units)(5 units) = 90 units²

4 0
3 years ago
stat: sample of 780 adults in the U.S.A., it was found that 80 of those had a pinworm infestation. You want to find the 99% conf
Anettt [7]

Answer: 554

Step-by-step explanation:

If prior population proportion is known, then the formula to find the sample size is given by :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

As per given description, we have

p= 0.1

E=0.025

Critical z-value for 95% confidence : z_{\alpha/2}=1.96

Then,

n=0.1(1-0.1)(\dfrac{1.96}{0.025})^2=553.1904\approx554

Hence, the minimum sample size required = 554.

7 0
3 years ago
What is the multiplicative inverse of −3/5?
bonufazy [111]

Answer:

The multiplicative inverse is -5/3

Step-by-step explanation:

Multiplicative inverse means we want to end up with 1

-3/5 * what =1

Multiply by 5 to clear the fraction

-3/5 * what *5 = 1*5

-3 * what = 5

Divide by -3 to isolate what

-3*what /-3 = 5/-3

what = -5/3

The multiplicative inverse is -5/3

4 0
3 years ago
What is the average of 3/8 + 2/4 + 5/8 + 7/8 + 1 1/8 + 1 5/8 + 1 7/8 + 4
melisa1 [442]

Answer:

1 3/8

Step-by-step explanation:

Well to find the average or the mean we need to add all the numbers,

3/8 + 2/4 + 5/8 + 7/8 + 1 1/8 + 1 5/8 + 1 7/8 + 4

= 11

Then we divide t by the number of numbers in the set.

11 ÷ 8 = 1 3/8

<em>Thus,</em>

<em>the average in the set is 1 3/8.</em>

<em />

<em>Hope this helps :)</em>

4 0
3 years ago
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