Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x= 2 1 x, equal

Question

stealth61 [152]

4 years ago

9

Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x= 2 1 x, equal

s, start fraction, 1, divided by, 2, end fraction.

Mathematics

2 answers:

Sergeeva-Olga [200] · Answer 1 · 2022-01-06T04:27:50+03:00

Sergeeva-Olga [200]4 years ago

5 0

For this case we have the following expression:
13-0.75w + 8x
We must evaluate for the following values:
w = 12
x = 1/2
Substituting the values we have:
13- 0.75 * (12) + 8 * (1/2) = 8
Answer:
The result after evaluating the expression is:
8

castortr0y [4] · Answer 2 · 2022-01-06T06:15:01+03:00

castortr0y [4]4 years ago

5 0

Answer:

the answer will be 8

Step-by-step explanation:

Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x= 2 1 ​ x, equal

Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x= 2 1 x, equal