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yuradex [85]
3 years ago
7

Andre builds a form for a new cement step. The Form he builds is 40.5in long, 10in deep, and 8in high. How much cement is needed

to fill the form? When you get the answer:Andre has enough cement to fill 3500in. He decides to change the length of the step so that he will use all of the cement. What will be the new length of the step?
Mathematics
2 answers:
lyudmila [28]3 years ago
6 0
The new length would be 173.15 inches long
pickupchik [31]3 years ago
5 0
New length is 43.75 inches long 
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Point K is rotated 90°. The coordinate of the pre-image point K was (2, –6) and its image K’ is at the coordinate (−6, −2). Find
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Answer:

A clockwise rotation.

Step-by-step explanation:

The rule for 90 degree clockwise rotation is (x,y) turns into (y,-x) therefore if you use your numbers (2,-6) and then use the 90 degree clockwise rotation rule it becomes (-6,-2)

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A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant
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Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10

Similarly, but exchanging the role of x and y, we compute the length of BC:

\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5

So, the area of the rectangle is \overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3

\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4

So, the area of the portion located in the third quadrant is \overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12

This means that the ratio between the two area is

\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}

If we want this ratio to be a percentage, just make sure that the denominator is 100:

\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%

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3 years ago
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