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wel
3 years ago
12

Measuring well-being is difficult for utilitarians because there A. is no precise unit of happiness. B. might be multiple things

that directly contribute to well-being. C. doesn't seem to be any method to compare the quantities of different benefits. D. all of the above
Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

There is no precise unit of happiness, there might be multiple things that directly contribute to well-being, there doesn't seem to be any method to compare the quantities of different benefits (All of the above.)

Step-by-step explanation:

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Four less than the quotient of a number and 4 is 14. What is the number? Let n be the unknown number.
Maru [420]
So the equation is n/4-4=14
then you +4 to both sides 
n/4-4=14 so now the equation is n/4=18 then you multiply 18 by 4 and get 72
   +4    +4
then to check your work
72/4-4=14
so N=72
Hope I helped :)

8 0
3 years ago
The boundary of the lawn in front of a building is represented by the parabola . The parabola is represented on the coordinate p
Colt1911 [192]
The boundary of the lawn in front of a building is represented by the parabola

y = (x^2) /16 + x - 2

And you have three questions which require to find the focus, the vertex and the directrix of the parabola.

Note that it is a regular parabola (its symmetry axis is paralell to the y-axis).

1) Focus:

It is a point on the symmetry axis => x = the x-component of the vertex) at a distance equal to the distance between the directrix and the vertex).

In a regular parabola, the y - coordinate of the focus is p units from the y-coordinate of the focus, and p is equal to 1/(4a), where a is the coefficient that appears in this form of the parabola's equation: y = a(x - h)^2 + k (this is called the vertex form)

Then we will rearrange the standard form, (x^2)/16 + x - 2 fo find the vertex form y = a(x-h)^2 + k

What we need is to complete a square. You can follow these steps.

1) Extract common factor 1/16 => (1/16) [ (x^2) + 16x - 32]

2) Add (and subtract) the square of the half value of the coefficent ot the term on x =>

16/2 = 8 => add and subtract 8^2 => (1/16) [ (x^2) + 16 x + 8^2 - 32 - 8^2]

3) The three first terms inside the square brackets are a perfect square trinomial: =>

(1/16) [ (x+8)^2 - 32 - 64] = (1/16) [ (x+8)^2  - 96] =>

(1/16) [(x+8)^2 ] - 96/16 =>

(1/16) (x +8)^2 -  6

Which is now in the form a(x - h)^2 + k,
where:

a = 1/16 , h = - 8, and k = -6

(h,k) is the vertex: h is the x-coordinate of the vertex, and k is the y-coordinate of the vertex.

=> a = 1/16 => p =1/4a = 16/4 = 4
 
y-componente of the focus = -6 + 4 = -2

x-component of the focus = h = - 8

=> focus = (-8, -2)

2) Vertex

We found it above, vertex = (h,k) = (-8,-6)


3) Directrix

It is the line y = p units below the vertex = > y = -6 - 4 = -10

y = -10   

 


4 0
4 years ago
Consider the following geometric sequence -5, 10, -20, 40,..... if the recursive formula for the sequence above expressed in the
MAXImum [283]
B is -5 and C is -2. Since -5 is the first number, a(1) is bc^0 and that would make c = 1. B would need to be -5. In the second number, since we know b is -5, c would need to be -2 and anything to the 2-1 is just the same value.
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3 years ago
If b+c-a/a, c+a-b/CA are in A.P., prove that a, b, c are in<br>Н.Р.​
SOVA2 [1]

Answer:I love thee fact that I am a straight a Student but I don't wanna help you dumb people

Step-by-step explanation:

3 0
3 years ago
Helpppp plzzzzzzzzzzzzzzz
marin [14]

Answer:

y= 0.2(0.05)^x

5 0
3 years ago
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