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wel
3 years ago
12

Measuring well-being is difficult for utilitarians because there A. is no precise unit of happiness. B. might be multiple things

that directly contribute to well-being. C. doesn't seem to be any method to compare the quantities of different benefits. D. all of the above
Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer:

There is no precise unit of happiness, there might be multiple things that directly contribute to well-being, there doesn't seem to be any method to compare the quantities of different benefits (All of the above.)

Step-by-step explanation:

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What is 540 simplified
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Since 540 is a whole number, it cannot be simplified anymore. 
4 0
3 years ago
After 10 years, Hamid's account earned $300 in interest. If the interest rate (in decimal form) is 0.06, how much did Hamid init
tester [92]

Answer:

  • p = I/(rt)
  • p = $500

Step-by-step explanation:

To solve the equation I=prt for p, divide by its coefficient, rt. That gives ...

  p = I/(rt)

__

Now, to answer the question, you can substitute the given values for I, r, t and you have ...

  p = $300/(0.06·10) = $500

Hamid initially invested $500.

6 0
3 years ago
2logx=3-2log(x+3) solve for x​
AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}

x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
What steps do i take to prove this? i have a few more
Maksim231197 [3]

Answer:

They are opposite angles. If you rotate the figure SQM 180 degrees counter clockwise, they will be the exact same triangle and therefore the exact same measure.

Step-by-step explanation:

5 0
3 years ago
Simplify. Your answer should only contain only positive exponents.
Xelga [282]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
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