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weeeeeb [17]
2 years ago
15

I went to many other places, I saw their answers and turns out the only answer I searched up was wrong!

Mathematics
2 answers:
topjm [15]2 years ago
8 0

Answer:

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Step-by-step explanation:

julia-pushkina [17]2 years ago
3 0

Answer:

whats the question tho

Step-by-step explanation:

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Maria solved the equation 34=x+19. Although her final answer was correct, she could have found it in a simpler way. how could sh
mamaluj [8]

Answer:

She could have subtracted 19 from both sides. Hope this helps :)

Step-by-step explanation:

3 0
3 years ago
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Does anyone know how to solve |4x+3|-9<5
elixir [45]

Answer in fraction form:   -17/4 < x < 11/4

Answer in decimal form:   -4.25 < x < 2.75

=======================================================

Work Shown:

|4x+3| - 9 < 5

|4x+3| < 5+9 .... adding 9 to both sides

|4x+3| < 14

-14 < 4x+3 <  14 .... see note at the bottom

-14-3 < 4x < 14-3 .... subtracting 3 from all sides

-17 < 4x < 11

-17/4 < x < 11/4 .... divide all sides by 4

-4.25 < x < 2.75

This says that x is between -4.25 and 2.75, but x is not equal to either endpoint.

Note: I used the rule that |x| < k becomes -k < x < k where k is a positive real number.

6 0
3 years ago
What is the value of p in the equation shown? <br> p3=0.064
Ne4ueva [31]
If you mean the question 3p=0.064 then to find the answer you divide 0.064 by 3 to get 0.213333.....
6 0
3 years ago
What is the equation of the line (in slope-intercept form) that passes through the point (5,−1) and is parallel to the line y=2x
tatyana61 [14]

Answer:

<h2>y = 2x - 11</h2>

Step-by-step explanation:

\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\===============================

\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-slope\\b-y-intercept\\\\==========================

\text{We have the equation of a line:}\ y=2x-7\to m_1=2.\\\\\text{The slope of a parallel line:}\ m_2=m_1=2.\\\\\text{We have the equation:}\\\\y=2x+b\\\\\text{Put the coordinates of the point (5, -1) o the equation:}\\\\-1=2(5)+b\\-1=10+b\qquad\tex\text{subtract 10 from both sides}\\-11=b\to b=-11\\\\\text{Finally:}\\\\y=2x-11

5 0
3 years ago
What's the area below?
Marina86 [1]
I honestly have no idea :) :S ur welcome
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