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weeeeeb [17]
2 years ago
15

I went to many other places, I saw their answers and turns out the only answer I searched up was wrong!

Mathematics
2 answers:
topjm [15]2 years ago
8 0

Answer:

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Step-by-step explanation:

julia-pushkina [17]2 years ago
3 0

Answer:

whats the question tho

Step-by-step explanation:

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The function y = f (x) is graphed below. What is the average rate of change of the function f(x) on the interval - 1 ≤ x ≤ 3?
jonny [76]

Answer:

\displaystyle -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Average Rate of Change: \displaystyle \frac{f(b) - f(a)}{b - a}

Step-by-step explanation:

<u>Step 1: Define</u>

Interval -1 ≤ x ≤ 3

a = -1, b = 3

f(a) = f(-1) = 4

f(b) = f(3) = -4

<u>Step 2: Find Average</u>

  1. Substitute in variables [ARC]:                     \displaystyle \frac{f(3) - f(-1)}{3 + 1}
  2. Substitute:                                                   \displaystyle \frac{-4 - 4}{3 + 1}
  3. [Fraction] Subtract/Add:                             \displaystyle \frac{-8}{4}
  4. [Fraction] Divide:                                        \displaystyle -2
4 0
3 years ago
Sugar was traditionally produced and sold as sugarloaves, which are cones of sugar wrapped in paper. Find the total surface area
Zolol [24]

Answer:

A = 326,73 cm²

Step-by-step explanation:

The area of a circular cone is area of the base (A₁ ) plus area lateral ( area of a circular sector of radius the slant height )

Then we proceed to calculate the area of the base A₁

diameter of circular base is 8 cm then the radius is 4 cm and the area is:

A₁ = π*r²  =  3,14* (4)²

A₁ = 3,1416*16   =  50,2656 cm²

Now Lateral area of the cone (A₂) is equal to the area of a circular sector with radius the slant height. We will calculate it, taken into account that this circular sector is part of a circle of radius the slant height.

Between the area of circular sector with radius the slant height and the area of the circle with the same radius there is a linear relation. That is we can calculate area of a circular sector by rule of three as follows:

The length of the circular sector is the length of the circle of the base of the cone, that is:

L = 2*π*(4)

L = 2*3,1416*4

L = 25,1328 cm

Then we have a circular sector of length 25,1328 cm

The area of the circle of radius 22 cm is:

A(c)  = π*(22)²     ⇒   A(c)  = 1520,5344 cm²

And the length of this circle is:

L(c)  =  2*π*(22)     ⇒   138,2304 cm

Then we apply a rule of three

For a length of      138,2304 cm  ⇒⇒⇒  (area)  1520,5344 cm²

Then for a length of  25,1328 cm   ⇒⇒⇒(area)   A₂ (??)

Therefore:

A₂ =  (25,1328)*1520,5344)/ 138,2304

A₂ = 276,4608 cm²

Then total area of the cone is:

A = A₁  +  A₂

A =  50,2656  +276,4608

A  = 326,7264 cm²

Round answer  A = 326,73 cm²

8 0
3 years ago
Read 2 more answers
A population of size 3,624 grows at a rate of 3% per year, compounded continuously. How big will the population be in 2 years?
rodikova [14]

Answer:

Step-by-step explanation:

The continuous compound formula is

y=Pe^{rt where P is the principle or starting value, r is the growth rate in decimal form, and t is the time in years. For us:

y=3624e^{(.03)(2)}\\y=3624e^{.06}\\y=3624(1.061836547)\\y=3848.09

which would probably round to just 3848 people.

8 0
3 years ago
If f(x)=x+8 and g(x)=-4-3 find (f+g)(x)
Lilit [14]

Answer:

(f+g)(x) = -3x+5

Step-by-step explanation:

f(x)=x+8 and g(x)=-4x-3

(f+g)(x) = f(x) + g(x)

             = x+8+-4x-3

             = -3x+5

3 0
3 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
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