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Nady [450]
3 years ago
12

Write an expression for: Five more sodas than twice the number of chips? And Daniela has 12 more books than Nicole?

Mathematics
1 answer:
Ahat [919]3 years ago
5 0
The expressions are.
5+2c
d=12+n
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Last summer, Marrero was at Newgrange, a stone mound in Ireland that has a diameter of 250 feet. He found a walkway 62 feet long
timofeeve [1]

Answer:

  • 108 ft

Step-by-step explanation:

The line connecting the center with the end of the walkway is radius and is the hypotenuse of the right triangle.

Horizontal leg is the distance x.

<u>Vertical leg has the length:</u>

  • (250)/2 - 62 = 63 ft

<u>Using Pythagorean theorem to find the length of x:</u>

  • x² = (250/2)² - 63²
  • x² = 125² - 63²
  • x² = 11656
  • x = √11656
  • x = 107.96 ≈ 108

7 0
2 years ago
Do not understand please help <br> Thank u
AysviL [449]

Answer:

43.4

Step-by-step explanation:

You will need to use the phythagoream therom, which is a² + b² = c².  Plug the values in for the variables to get 7² + b² = 44², (c would equal the hypothenuse because the hypothenuse is the longest side of the triangle.)  Square the values to get 49 + b² = 1936.  Subtract 49 from both sides to get b² = 1887, then take the square root of both sides to get b = 43.4 (rounded to the nearest tenth.)  

I am really sorry if I'm wrong, but have a good day/night!  :)

6 0
2 years ago
Read 2 more answers
How to simplify the expressions of 5p-5-10-2p
Arada [10]

Answer:

3p - 15

Step-by-step explanation:

5p - 2p = 3p

-5 - 10 = -15

3p + - 15 = 3p - 15

4 0
2 years ago
PLZ ANSWER THIS<br> thanksssss
just olya [345]

Answer:

It should be C) 11+ 3 5/8

Step-by-step explanation:

5 0
2 years ago
Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag
VLD [36.1K]

Hey~freckledspots!\\----------------------

We~will~solve~for~i^{425}!

Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\

Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------

Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------

Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------

Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------

Answer:\\\large\boxed{-1+i}\\----------------------

Hope~This~Helped!~Good~Luck!

8 0
3 years ago
Read 2 more answers
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