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Ganezh [65]
3 years ago
11

Suppose player 2 can choose its strategy before player 1, that player 1 observes player 2's choice before making her decision, a

nd that this move structure is known by both players. what outcome would you expect?
Business
1 answer:
Anestetic [448]3 years ago
7 0
The outcome i would expect from this would be player 1 copying player 2 and following player 2 to see what happens after then maybe change his strategy.

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Why do some workers lose their job when the minimum wage is​ increased?
Julli [10]
The company can't afford to pay their employees. If you have 100$ you can have ten people working for 10$ an hour and pay everyone for one hour. You can't have 10 people getting paid 20$ because the company would lose money. So if they are paid 20$ per hour, the company can only afford to hire 5 employees. 
4 0
4 years ago
Read 2 more answers
Unemployment would cause an economy to Group of answer choices produce outside its production possibilities frontier. produce in
bagirrra123 [75]

Answer:

The correct answer is: produce inside its production possibilities frontier.

Explanation:

The production possibility frontier shows the maximum possible combination of two goods that an economy can produce using all the available resources and state of technology.

Unemployment in an economy means that all the available resources are not being completely used. So, the economy will operate at a point inside the production possibility curve.

Production at this point will be feasible but allocatively inefficient.

3 0
3 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
4 years ago
Cogswell cola purchased a machine for $237,500. The firm paid another $5,750 for delivery and installation. In addition the firm
Novay_Z [31]

Based on the cost of purchasing the machine and the delivery and installation fees, the initial outlay is $243,250

<h3>How much is the initial outlay?</h3>

This can be found as:

= Cost of purchasing machine + Installation and delivery cost

Solving gives:

= 237,500 + 5,750

= $243,250

Find out more on fixed asset capitalization at brainly.com/question/25355478

#SPJ1

3 0
2 years ago
"Income tax was $175,000 for the year. Income tax payable was $30,000 and $40,000 at the beginning and end of the year, respecti
kolezko [41]

Answer:

Cash payments for income tax  = $165000

so correct option is C. 165,000

Explanation:

given data

Income tax = $175,000

beginning tax payable = $30,000

end of the year tax payable = $40,000

to find out

Cash payments for income tax reported on the statement of cash flows

solution

we get here Cash payments for income tax that is express as

Cash payments for income tax  = Income tax  + beginning tax payable - end of the year tax payable      ..............................1

put here value we get

Cash payments for income tax  = $175000 + $30000 - $40000

Cash payments for income tax  = $165000

so correct option is C. 165,000

5 0
3 years ago
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