All categories

3 years ago

HELPP(05.02)The area of the parallelogram below is ____ square meters.

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

42m^2

Step-by-step explanation:

So to find the area of a ||-gram, its base*height-

so the base of the shape is 6m*by the height(7m)=42m^2

Hope this is right!

~Sof :P~

Annette [7]3 years ago

5 0

Answer:

The answer to your question is 42 m²

Step-by-step explanation:

Data

Base = 6 m

Height = 7 m

Formula

To calculate the area of a parallelogram just use the formula and substitute the values given, do not consider number 2.

Area = base x height

Substitution

Area = 6 x 7

Simplification and result

Area = 42 m²

You might be interested in

xy==16−????2????3−16???? is symmetric about the x-axis. (If ???? gives us the point (x,y), then −???? will give (x,−y) ). At whi

mote1985 [20]

Answer: The expression for a and y are not clear, however whatever expressions you are give, you can use the same approach as solved in the attached file.

At which x value is the tangent to this curve horizontal = 176/3

What is the total area inside the loop = 546.13 square unit

Step-by-step explanation:

The steps and appropriate derivation is as shown in the attachment.

7 0

3 years ago

Solve 2x^2 - 7x - 15 = 0. <br> a, (3/2,-5)<br> b (-3/2,5)<br> c ()

Brut [27]

For this case we must solve the following quadratic equation:

$2x ^ 2 -7x -15 = 0$

We must apply the following formula:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

We have to:

$a = 2\\b = -7\\c = -15$

Substituting we have:

$x = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (2) (- 15)}} {2 (2)}\\x = \frac {7 \pm \sqrt {49 + 120}} {4}\\x = \frac {7 \pm \sqrt {169}} {4}\\x = \frac {7 \pm13} {4}$

Thus, the solutions are:

$x_ {1} = \frac {7 + 13} {4} = \frac {20} {4} = 5\\x_ {2} = \frac {7-13} {4} = \frac {-6} {4} = - \frac {3} {2}$

ANswer:

$x_ {1} = 5\\x_ {2} = - \frac {3} {2}$

4 0

3 years ago

Find the distance between point P and line ℓ.

prisoha [69]

The distance between the line containing the points (0,-3) and (7,4) and the point P(4,3) is d =√2 units.

<h3>What is the distance between a line and a point?</h3>

The distance between the line ax +by +c =0 and the point (x₁, y₁) is given by:

$d=\frac{|ax_{1}+by_{1}+c|}{\sqrt{a^2+b^2}}$

Given that, the line passes through the points (0,-3) and (7,4).

The equation of the line is given by:

$y -(-3)=\frac{4-(-3)}{7-0}(x-0)\\\\y+3=x\\\\x-y-3=0$

Now, the distance between the line x - y - 3 = 0 and point (4,3) is:
$d=\frac{|1\times4+(-1)\times3+(-3)|}{\sqrt{1^2 +(-1)^2}}\\\\d=\frac{2}{\sqrt{2}}\\\\d=\sqrt{2}$

Hence, the distance between the line containing the points (0,-3) and (7,4) and the point P(4,3) is d =√2 units.

Learn more about the distance between a line and a point:
brainly.com/question/11558698

#SPJ1

4 0

1 year ago

What is the difference between the highest and the lowest temperature, -6 -8 -4 7 6 -2

vampirchik [111]

The difference between the <span>highest and the lowest temperature is 9 because the highest number is 7 and the lowest number is -2 so the difference is 9.</span><span />

4 0

3 years ago

My little brother asked for help and I don't even understand it. Can someone explain this for us?

frozen [14]

1. NIL
2. ZERO
3. OH
4. NOUGHT
5. LOVE

Hope this helps!

6 0

3 years ago

Read 2 more answers