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arsen [322]
3 years ago
14

PLEASE PLEASE HELP ASAP

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer: basically just set them equal and solve

Step-by-step explanation: vertical angles are xongruent

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Assume the rate of inflation is ​8% per year for the next 2 years. What will be the cost of goods 2 years from​ now, adjusted fo
Paha777 [63]
<h3>Answer: $326.59</h3>

==============================================

Work Shown:

F = future value

P = present value = 280

r = rate of inflation in decimal form = 0.08

t = elapsed time in years = 2

---------

F = P*(1+r)^t

F = 280*(1+0.08)^2

F = 326.592

F = 326.59

8 0
3 years ago
Pls help best answer will get brainiest
agasfer [191]

Answer:

Point A and point B have 11 units between

Step-by-step explanation:

If the distance between 0 and 10 is 10 also known as the absolute value, you just add one more unit because it starts at -1

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Hope this helps :)

8 0
3 years ago
If you know it please tell me it would help a lot
geniusboy [140]
7n \le 21

Divide both sides by 7.

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For example, n can be 1, 2, 3.
5 0
3 years ago
Nancy sells handcrafted bracelets at a flea market for $6. If her monthly fixed costs are $625 and each bracelet cost her $1.75
Mandarinka [93]
148, 6-1.75=5.25, then.... 625/5.25& round up.... its 148.
7 0
3 years ago
Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object
vovikov84 [41]

(a)

We can see that

this is a straight line

and this is the graph of velocity

we know that

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so, slope of curve of velocity is acceleration

so, we will find slope of this line

We can select any two points

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we can use slope formula

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug points

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m=0.6

we know that slope of line is always constant irrespective of any value of t

so, acceleration will always be same irrespective of any value of t

so, we will get acceleration

a(t)=0.6m/s^2............Answer

(b)

we can see that acceleration is constant

and we know that

derivative of constant is always 0

so, instantaneous rate of acceleration at t=10s is 0........Answer

7 0
3 years ago
Read 2 more answers
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