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arsen [322]
3 years ago
14

PLEASE PLEASE HELP ASAP

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer: basically just set them equal and solve

Step-by-step explanation: vertical angles are xongruent

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Explain how to use a horizontal number line<br> to order four fractions from least to greatest.
horsena [70]

Answer:

To order fractions from least to greatest, start by finding the lowest common denominator for all of the fractions. Next, convert each of the fractions by dividing the lowest common denominator by the denominator and then multiplying the top and bottom of the fraction by your answer.

Step-by-step explanation:

Solution for the above problem: We first find the least common denominator by finding the least common multiple for 4, 3, 2, 6, and 8. We find the LCM by the prime factorization method. Next, place the fractions in order from least to greatest.

4 0
3 years ago
Finish the polynomial by adding one number to make it a perfect square<br><br> x^2+18x+
dsp73

Answer:

81

Step-by-step explanation:

{x}^{2}  + 18x + {(( \frac{1}{2})(18)) }^{2}

{x}^{2}  + 18x +  {9}^{2}

{x}^{2}  + 18x + 81

{(x + 9)}^{2}

6 0
2 years ago
Use the given information to find the length of a circular arc. Round to two decimal places.the arc of a circle of radius 11 inc
sattari [20]

Answer:

The length of the circular arc is 8.64 inches

Step-by-step explanation:

Length of circular arc (L) = central angle/360° × 2πr

central angle = pie/4 = 45°, r (radius) = 11 inches

L = 45°/360° × 2 × 3.142 × 11 = 8.64 inches (to two decimal places)

7 0
3 years ago
Read 2 more answers
Carmen Martinez
klemol [59]
  • (4,4)
  • (10,7)

\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}

\\ \sf\longmapsto m=\dfrac{7-4}{10-4}

\\ \sf\longmapsto m=\dfrac{3}{6}

\\ \sf\longmapsto m=\dfrac{1}{2}

\\ \sf\longmapsto m\approx0.5

6 0
3 years ago
Read 2 more answers
Pls help, will give brainliest
Alexeev081 [22]

Answer:

see image

Step-by-step explanation:

Hope this is clear enough, if not feel free to ask me any questions.

3 0
3 years ago
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