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Ede4ka [16]
3 years ago
10

Solve and check the following equation algebraically. 1/2(x + 32) = -10

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
Solve :
1/2(x + 32) = -10....multiply both sides by 2
x + 32 = -10 * 2
x + 32 = -20
x = -20 - 32
x = - 52 <===

check :
1/2(x + 32) = -10.....when x = -52
1/2(-52 + 32) = -10
1/2(-20) = -10
-20/2 = -10
-10 = -10 (correct)

zhannawk [14.2K]3 years ago
4 0
1/2(x + 32) = -10

(x + 32) = - 20

x = -32 - 20

x = - 52
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Let's solve your equation step-by-step.

2(3x−1)=−6x−2

Step 1: Simplify both sides of the equation.

2(3x−1)=−6x−2

(2)(3x)+(2)(−1)=−6x+−2(Distribute)

6x+−2=−6x+−2

6x−2=−6x−2

Step 2: Add 6x to both sides.

6x−2+6x=−6x−2+6x

12x−2=−2

Step 3: Add 2 to both sides.

12x−2+2=−2+2

12x=0

Step 4: Divide both sides by 12.

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Answer:

x=0

HOPE THIS HELPS!!! :)

5 0
2 years ago
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Step-by-step explanation:

we know ,

area of circle =πr^2

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Answer:

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