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Marrrta [24]
2 years ago
13

Please help me asap.

Mathematics
1 answer:
Makovka662 [10]2 years ago
6 0

The first one is the answer you're looking for

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What is the area of the circle?
Tanzania [10]
Area = \pi * r^2
= \pi * 1.8^2
= 10.1787602m^2
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2 years ago
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Given the function f(x) = log3 (x + 1), determine f^−1(2).
zavuch27 [327]
Given:  <span>f(x) = log3 (x + 1), look for f^-1 (2)

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</span><span>f^-1 (2) = 8</span>
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Find the solutions of the congruence 12x2 + 25x ≡ 10 (mod 11). [Hint: Show the congruence is equivalence to the congruence 12x2
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Step-by-step explanation:

5 0
3 years ago
Which is not a solution of sin 20 = 1?<br> A = 90<br> B = 45<br> C = 225<br> D = - 135
koban [17]
If you plug in 90 into theta, the expression becomes sin(180), which has a value of zero. Therefore 90 cannot be a solution to this equation. Hope this helps.
6 0
1 year ago
What is the solution?
Ilia_Sergeevich [38]

Answer:

A. {3+7i,3-7i}

Step-by-step explanation:

The given equation  is  x^2-6x+58=0

Use the quadratic formula with a=1,b=-6 and c=58

Recall the quadratic formula;

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

We substitute the given values to get;

x=\frac{--6\pm \sqrt{(-6)^2-4(1)(58)} }{2(1)}

x=\frac{6\pm \sqrt{36-232} }{2}

x=\frac{6\pm \sqrt{-196} }{2}

Recall that;

\sqrt{-1}=i

x=\frac{6\pm 14i}{2}

x=3\pm 7i

x=3+7i or x=3-7i

8 0
3 years ago
Read 2 more answers
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