6 + 11 = 17" of string.
draw both pieces of string showing the missing number as the total length of both strings.
BSA = hw ÷ 60
We have:
h = 184
w = 83
BSA = (184)(83) ÷ 60
BSA = 15272 ÷ 60
BSA = 254.5 (Rounded to one decimal place)
Answer:
a = – 8
Step-by-step explanation:
From the question:
When P(x) = 2x³ – ax² + 4x – 4 is divided by x – 1, it gives a reminder of 10.
To obtain the value of a, we shall equate x – 1 to 0 as illustrated below:
x – 1 = 0
x = 0 + 1
x = 1
Next, we shall substitute the value of x into 2x³ – ax² + 4x – 4 and equating it to 10 as illustrated below:
2x³ – ax² + 4x – 4 = 10
x = 1
2(1)³ – a(1)² + 4(1) – 4 = 10
2 – a + 4 – 4 = 10
2 – a = 10
Collect like terms
– a = 10 – 2
– a = 8
Divide through by –1
a = – 8
Therefore, the value of a is –8.
Answer:
See Explanation
Step-by-step explanation:
A <u>prime number</u> is a number that has only two factors, by 1 and itself.
A <u>composite number</u> on the other hand are numbers which have more than two factors.
To determine the number of prime cards needed to build each composite number, we first express the number as a product of its prime factors.
These are:
4=2X2
6=2X3
8=2X2X2
9=3X3
10=2X5
12=2X2X3
14=2X7
15=3X5
16=2X2X2X2
18=2X3X3
20=2X2X5
21=3X7
22=2X11
24=2X2X2X3
26=2X13
27=3X3X3
28=2X2X7
30=2X3X5
32=2X2X2X2X2
33=3X11
34=2X17
35=5X7
36=2X2X3X3
38=2X19
39=3X13
40=2X2X2X5
42=2X3X7
44=2X2X11
45=3X3X5
46=2X2X13
48=2X2X2X2X3
49=7X7
50=2X5X5
Therefore for each of the numbers, those are the prime number cards to be used.
Take for example, the number 50, the prime numbers that will be used to build 50 are the prime factors of 50.
50=2 X 5 X 5
Therefore, its prime factors are 2 and 5.
We will use the following prime number cards:
- 1 card with prime number 2
- 2 cards with prime number 5
Answer:
Histogram
Step-by-step explanation:
Im pretty sure its a histogram because all other kinds of graphs wouldn't properly represent the data
