X= 2 over 9 or in decimal form 0.2222....
Answer:
A) 4
Step-by-step explanation:
There are a couple of ways to get this but this is how I did it:
1. Multiply the second equation by 1/4 to get the same fraction for y as the one in the first equation
1/4 x + 1/8 y = 2
1/4 (1/3 x + 1/2 y = 4)
1/12 x + 1/8 y = 1
2. Subtract the first equation from the new equation
1/12 x + 1/8 y = 1
<u> - 1/4 x - 1/8 y = -2</u>
-1/6 x= -1
3. Divide both sides by -1/6
<u>-1/6</u> x= <u>-1</u>
-1/6 -1/6
x = 6
4. Substitute 4 in for x in the original equation:
1/4 (6) + 1/8y = 2
6/4 + 1/8y = 2
1/8y = 1/2
y = 4
Use the distributive property.
4(4a + 5) = 4 * 4a + 4 * 5 = 16a + 20
Answer: 16a + 20
Answer:
The other dimension of the pasture (width) is ![1.625\ mi](https://tex.z-dn.net/?f=1.625%5C%20mi)
Step-by-step explanation:
In this problem I assume that the pasture has the shape of a rectangle.
Let
x -----> the length of the pasture
y -----> the width of the pasture
we know that
The area of the pasture (rectangle) is equal to
![A=xy](https://tex.z-dn.net/?f=A%3Dxy)
we have
![A=0.65\ mi^{2}](https://tex.z-dn.net/?f=A%3D0.65%5C%20mi%5E%7B2%7D)
![x=0.4\ mi](https://tex.z-dn.net/?f=x%3D0.4%5C%20mi)
substitute and solve for y
![0.65=0.4y](https://tex.z-dn.net/?f=0.65%3D0.4y)
![y=0.65/0.4](https://tex.z-dn.net/?f=y%3D0.65%2F0.4)
![y=1.625\ mi](https://tex.z-dn.net/?f=y%3D1.625%5C%20mi)
Answer:
A. 42½ units
Step-by-step explanation:
the volume = 5×2×4¼ = 10×4¼ = 42½