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pshichka [43]
3 years ago
6

Given the point slope equation y – 190 = 22(x-19) convert it to slope intercept form

Mathematics
1 answer:
ELEN [110]3 years ago
6 0

Answer:

Y = mx + b

Y = 22x + 190

M is the slope

Y is the y intercept

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Find the equation of the plane through the point p=(5,5,4)p=(5,5,4) and parallel to the plane 5x+2y−z=−6.
Anna35 [415]
The unit normal for the given plane is <5,2,-1>.
The equation of the plane parallel to the given plane passing through (5,5,4) is therefore
5(x-5)+2(y-5)-1(z-4)=0
simplify =>
5x+2y-z=25+10-4=31

Answer: the plane through (5,5,4) parallel to 5x+2y-z=-6 is 5x+2y-z=31
7 0
3 years ago
The graph below shows the solution to which system of inequalities?
Archy [21]

Answer:

C

Step-by-step explanation:

The horizontal line, y=2, is solid and shaded above, so it represents

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2 years ago
A ladder leans against the side of a house. The angle of elevation of the ladder is 62 degrees and the top of the ladder is 14 f
marysya [2.9K]

Answer:

7.4 feets

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5 0
3 years ago
Find the x and y intercepts of -5x+y=10
liubo4ka [24]

Answer:

x-int: (2, 0)

y-int: (0, -5)

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To find the y-intercept, substitute in 0 for x.

hope this helps please make mine the brainliest

7 0
3 years ago
How many even 5-digit numbers can be formed from the numbers 1, 2, 4, 7, 8 if no digit is repeated in a number? A. 72 B. 120 C.
katovenus [111]
Hello,

Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)

It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24

Thus there are 3*24=72 possibilities.

Answer A

If you do'nt believe run this programm

DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
    FOR i2 = 1 TO 5
        IF i2 <> i1 THEN
            FOR i3 = 1 TO 5
                IF i3 <> i2 AND i3 <> i1 THEN
                    FOR i4 = 1 TO 5
                        IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
                            FOR i5 = 1 TO 5
                                IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
                                    nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
                                    IF nb MOD 2 = 0 THEN
                                        tot = tot + 1
                                    END IF
                                END IF
                            NEXT i5
                        END IF
                    NEXT i4
                END IF
            NEXT i3
        END IF
    NEXT i2
NEXT i1
PRINT "tot="; tot
END


7 0
3 years ago
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