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2 years ago

7

What would 18 times 105 be?

2 answers:

yarga [219]2 years ago

7 0

18 multiplied by 105 would be 1,890

masha68 [24]2 years ago

5 0

Answer:

The answer would be 1890

hope it helped

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Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

There are 10 pens in a box. There are x red pens in the box. All the other pens are blue. Jack takes at random two pens from the

expeople1 [14]

The probability that one of each color is selected is $\frac{10x - x^2}{45}$

<h3>Probabilities</h3>

The probability of an event is the chances of the said event

The given parameters are:

Total = 10
Red = x
Blue = 10 - x

<h3>Calculating the required probability</h3>

The probability that one of each color is selected is calculated as follows:

$P = P(Blue) \times P(Red) + P(Red) \times P(Blue)$

So, we have:

$P = \frac{10 - x}{10} \times \frac{x}{9} + \frac{x}{10} \times \frac{10 - x}{9}$

This gives

$P = \frac{x(10 - x)}{90} +\frac{x(10 - x)}{90}$

Take LCM

$P = \frac{2x(10 - x)}{90}$

Simplify the above expression

$P = \frac{x(10 - x)}{45}$

Expand

$P = \frac{10x - x^2}{45}$

Hence, the probability that one of each color is selected is $P = \frac{10x - x^2}{45}$

Read more about probabilities at:

brainly.com/question/7965468

4 0

2 years ago

A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear). Round to the nea

dexar [7]

15+12+6= total number of marbles
33= total
Not clear marbles = 15+12 or 27
27 /33
.818181
82 percent

8 0

3 years ago

3 tens+7 thousand+5 ten thosands+2ones +6 hundreds

Lady_Fox [76]

57,682
I got this by putting the numbers in their place

7 0

3 years ago

Read 2 more answers

Josiah went to the local barber to get his haircut. It cost $18 for the haircut. Josiah tipped the barber 15%. What was the tota

salantis [7]

Answer:

2.70

Step-by-step explanation:

5 0

2 years ago