Let the first number be = x
Let the second number which is consecutive be = x+1
As given, the product of two consecutive square numbers is 144
Square rooting both sides we get
or 
Neglect the negative value so we get x=3
Hence, one number is 3 and the consecutive number is = 3+1=4
The square of the numbers are 9 and 16.
Hello,
4. you have sequences defined by the first term and a recursive relation.
Take n = 2, it gives
, right?
But you know 
so 
This is the second term. You are asked to find the first three terms.
Now, let's take n = 3
So the first three terms are 3, 6, 12.
6.
8.
10.
Do not hesitate if you have any question.
Thank you
Considering the graph of the velocity of the car, it is found that the interval in which it was stopped at a traffic light was:
Between 3 and 4 minutes.
<h3>When is a car stopped at a traffic light?</h3>
When a car is stopped at a traffic light, the car is not moving, that is, it's velocity is of zero.
In this problem, the graph gives the <u>velocity as a function of time</u>, and it is at zero between 3 and 4 minutes, hence the interval in which it was stopped at a traffic light was:
Between 3 and 4 minutes.
More can be learned about the interpretation of the graph of a function at brainly.com/question/3939432
#SPJ1
For the answer to the question above, <span>f x is the number of days she works, she'll earn $90x </span>
<span>After buying the laptop, she'll have $90x - $700 left over, which will pay for ($90x - $700) / $150 days of travel. So we have y = ($90x - $700) / $150 = (9x - 70) / 15 = 0.6x - (14/3) </span>
<span>Note that y can't be negative. Also, if y = 0, then Emma doesn't get to travel at all, so we should avoid that. So we have: </span>
<span>0.6x - (14/3) > 0 </span>
<span>0.6x > 14/3 </span>
<span>x > (14/3) / 0.6 </span>
<span>x > 70/9 </span>
<span>The question says that x can be up to 40, so the domain is 70/9 < x <= 40 </span>
<span>That's approximately 7.777... < x <= 40 </span>
<span>Multiply those numbers by 0.6 and then subtract 700 to get the range: </span>
<span>0 < y <= 58/3 </span>
<span>That's approximately 0 < y <= 19.333</span>
Your answer is D.
Plug in the x value into the equation and ou will get your answer.
(1+4)^2 = 5^2 = 25
So on and so on
