First, the bigger square's area is 20*20= 400 cm^2
second, the circle's area is ¶r^2 = ¶(20/2)^2 = ¶(10)^2 = 100¶ cm^2
third, smaller square-- if we imagine it as 4 parts as 4 right triangles-- 1 part will be 1/2*(20/2)(20/2) = 1/2 (10)(10) = 50 cm^2 then the area of the smaller square is 4*50 = 200 cm^2
so the shaded parts = circle - smaller square =100¶ - 200 cm^2
the answer is 2
Answer:
- value: $66,184.15
- interest: $6,184.15
Step-by-step explanation:
The future value can be computed using the formula for an annuity due. It can also be found using any of a variety of calculators, apps, or spreadsheets.
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<h3>formula</h3>
The formula for the value of an annuity due with payment P, interest rate r, compounded n times per year for t years is ...
FV = P(1 +r/n)((1 +r/n)^(nt) -1)/(r/n)
FV = 5000(1 +0.06/4)((1 +0.06/4)^(4·3) -1)/(0.06/4) ≈ 66,184.148
FV ≈ 66,184.15
<h3>calculator</h3>
The attached calculator screenshot shows the same result. The calculator needs to have the begin/end flag set to "begin" for the annuity due calculation.
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<h3>a) </h3>
The future value of the annuity due is $66,184.15.
<h3>b)</h3>
The total interest earned is the difference between the total of deposits and the future value:
$66,184.15 -(12)(5000) = 6,184.15
A total of $6,184.15 in interest was earned by the annuity.
Answer:
Which points are collinear?
G, A, and T
G, E, and T
A, T, and E
G, A, and E
Step-by-step explanation:
Answer:
84%
Step-by-step explanation:
The empirical rule tells you that 68% of the standard normal distribution is within 1 standard deviation of the mean. The distribution is symmetrical, so the amount in the lower tail is (1 -68%)/2 = 16%.
Since the number you're interested in, 240, is one standard deviation above the mean (200 +40), the percentage of interest is the sum of the area of the central part of the distribution along with the lower tail:
68% + 16% = 84%.
Answer:
see attached
Step-by-step explanation:
For x < -6, the function has a slope of -1 and an x-intercept of -6.
For x > -6, the function has a slope of 2 and an x-intercept of -6.
The function given here is not defined at x=6, so there is a hole at (-6, 0).