All categories

3 years ago

A circle has center (5, –4) and radius 8. Which gives the equation for the circle

Mathematics

1 answer:

andrew-mc [135]3 years ago

5 0

Answer:

(x-5)^2 + (y+4)^2 =64

Step-by-step explanation:

You might be interested in

What is the value of c? 50 100 84

kkurt [141]

THE VALUE C IS NUMBER 4 WHICH IS 84 DEGREES WHICH IS AND OBTUSE ANGLE

4 0

2 years ago

Read 2 more answers

Factor complete x^2 +2x-15

Murrr4er [49]

Answer:

( x - 3 ) ( x + 15 )

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Please help us with math test

laila [671]

Answer:

the answer is 420 gram brainliest plzz

6 0

3 years ago

Read 2 more answers

PLEASE HELP!!

Lapatulllka [165]

Step-by-step explanation:

Convert the equation to the slope-intercept form (y = mx + b):

$-5x-3y=-7$ add 5x to both sides

$-3y=5x-7$ divide both sides by (-3)

$y=-\dfrac{5}{3}x+\dfrac{7}{3}$

Choose any three values of x and calculate the values od y:

for x = -1:

$y=-\dfrac{5}{3}(-1)+\dfrac{7}{3}=\dfrac{5}{3}+\dfrac{7}{3}=\dfrac{12}{3}=4\to(-1,\ 4)$

for x = 2:

$y=-\dfrac{5}{3}(2)+\dfrac{7}{3}=-\dfrac{10}{3}+\dfrac{7}{3}=-\dfrac{3}{3}=-1\to(2,\ -1)$

for x = 5

$y=-\dfrac{5}{3}(5)+\dfrac{7}{3}=-\dfrac{25}{3}+\dfrac{7}{3}=-\dfrac{18}{3}=-6\to(5,\ -6)$

7 0

2 years ago

From a bowl containing five red, three white, and seven blue chips, select four at random and without replacement. Compute the c

snow_lady [41]

Answer:

The probability is $\frac{5}{9}$

Step-by-step explanation:

Let A be the event of one red, zero white, and three blue chips,

And, B is the event of at least three blue chips,

Since, A ∩ B = A (because If A happens that it is obvious that B will happen )

Thus, the conditional probability of A if B is given,

$P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}=\frac{P(A)}{P(B)}$

Now, red chips = 5,

White chips = 3,

Blue chips = 7,

Total chips = 5 + 3 + 7 = 15

Since, the probability of one red, zero white, and three blue chips, when four chips are chosen,

$P(A)=\frac{^5C_1\times ^3C_0\times ^7C_3}{^{15}C_4}$

$=\frac{5\times 35}{1365}$

$=\frac{175}{1365}$

$=\frac{5}{39}$

While, the probability that of at least three blue chips,

$P(B)=\frac{^8C_1\times ^7C_3+^8C_0\times ^7C_4}{^{15}C_4}$

$=\frac{8\times 35+35}{1365}$

$=\frac{315}{1365}$

$=\frac{3}{13}$

Hence, the required conditional probability would be,

$P(\frac{A}{B})=\frac{5/39}{3/13}$

$=\frac{65}{117}$

$=\frac{5}{9}$

4 0

3 years ago