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Ksenya-84 [330]
2 years ago
8

There are 3 yellow, 4 blue, 3 green, and 2 red candies in a bag. Without looking, Brian reaches into the bag and pulls out one p

iece of candy. What is the probability Brian will pull out a yellow candy?
Mathematics
1 answer:
olga55 [171]2 years ago
7 0
<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ First, we need to figure out the total number of candies:

3 + 4 + 3 + 2 = 12

Keep this number in mind as it will be the denominator

There are 3 yellow candies so the probability would be:

\frac{3}{12} or \frac{1}{4}

➶Hope This Helps You!

➶Good Luck :)

➶Have A Great Day ^-^

↬ Hannah ♡

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\frac{a}{8}  =  - 4 \\  =  > a \:  =  - 4 \times 8 \\  =  > a \:  =  - 32 \\

<h3>Answer is -32.</h3>

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3 years ago
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Izara built a fence for her horses. The fence was 210 feet long. She put a fence post in the ground at the start of the fence an
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3 years ago
What is the lateral area of the pyramid
Mkey [24]

Answer:

43.75 ft²

Step-by-step explanation:

s_l = (l√(w/2)² + h²) + (w√(l/2)² + h²)

l & w become 3.5, and h becomes 6.

<em />s_l<em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)

<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>

<em />s_l = 2(3.5√(3.5/2)² + 6²)

<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>

<em />s_l<em> </em>= 2(3.5√1.75² + 6²)

<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>

s_l = 2(3.5√3.0625 + 36)

<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>

<em />s_l = 2(3.5√39.0625)

<em>Step 5: The square root of 39.0625 is 6.25.</em>

<em />s_l<em> </em>= 2(3.5 * 6.25)

<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>

<em />s_l = 2(21.875)

<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>

<em />s_l = 43.75 ft²

The lateral area of this pyramid is 43.75 ft².

<em />

<em />

3 0
2 years ago
An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude
AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

p\pm z*\sqrt{\frac{p*(1-p)}{n} }

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students

60 students were in the sample.

8 0
3 years ago
Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 133 to 193 cm and
yawa3891 [41]

Answer:

The weight of an adult male who is 172 cm tall is 89.36 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

\hat y=-105+1.13x

Here

<em>y</em> = weight of a person

<em>x</em> = height of a person

The information provided is:

\bar x=167.90\ cm\\\bar y=81.47\ kg\\r (X, Y) = 0.228\\p-value=0.023\\\alpha =0.05

The hypothesis to test the significance of the correlation between height and weight is:

<em>H₀</em>: There is no relationship between the height and weight, i.e. <em>ρ</em> = 0.

<em>Hₐ</em>: There is a relationship between the height and weight, i.e. <em>ρ </em>≠ 0.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

<em>p</em>-value = 0.023 < <em>α</em> = 0.05

The null hypothesis was rejected at 5% level of significance.

Thus, concluding that there is a relationship between the height and weight.

Compute the weight of an adult male with height, <em>x</em> = 172 cm as follows:

\hat y=-105+1.13x

  =-105+(1.13\times 172)\\=-105+194.36\\=89.36

Thus, the weight of an adult male who is 172 cm tall is 89.36 kg.

5 0
3 years ago
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