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Dmitriy789 [7]
4 years ago
11

Describe the graph of the equation y = 4. Is the equation a function? vertical line; yes horizontal line; no vertical line; no h

orizontal line; yes
Mathematics
1 answer:
Alik [6]4 years ago
8 0
Yes it is a function. It is a horizontal line. 

Every point on this line is of the form (x,4) where x can be any number you want. The y coordinate is fixed at 4 and cannot change. Two points on this line are (0,4) and (1,4). The horizontal line goes through 4 on the vertical y axis. 

Why is it a function? Because it is impossible to draw a vertical line through more than one point on the graph of y = 4. The graph passes the vertical line test. Put another way, for any x input, there is exactly one y output. 

Side Note: y = 4 is the same as y = 0x+4. Note how its in the form y = mx+b
m = 0 is the slope
b = 4 is the y intercept
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What are the zeros of the quadratic function f(x) = 2x2 + 8x – 3?
jenyasd209 [6]

Answer:

  x=-2-\sqrt{\dfrac{11}{2}}\ \text{and}\ x=-2+\sqrt{\dfrac{11}{2}}

Step-by-step explanation:

My favorite way to go at this is to look at a graph. It shows the vertex at (-2, -11). Since the leading coefficient is 2, this means the roots are ...

  -2\pm\sqrt{\dfrac{11}{2}}

where the 2 in the denominator of the radical is the leading coefficient.

__

You can also use other clues:

  • the axis of symmetry is -b/(2a) = -8/(2(2)) = -2, so answer choices C and D don't work
  • the single change in sign in the coefficients (+ + -) tells you there is one positive real root, so answer choice B doesn't work.

The first answer choice is the only one with values symmetrical about -2 and one of them positive.

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You may be expected to use the quadratic formula:

  x=\dfrac{-b\pm\sqrt{b^-4ac}}{2a}=\dfrac{-8\pm\sqrt{8^2-4(2)(-3)}}{2(2)}\\\\=\dfrac{-8}{4}\pm\dfrac{\sqrt{88}}{4}=-2\pm\sqrt{\dfrac{11}{2}}

7 0
3 years ago
Apples weight about 12 ounces each.Ronald bought 4 apples.how many pounds of apples did he buy?
Zarrin [17]

Answer:

3 lbs

Step-by-step explanation:

4 0
3 years ago
in the previous question, what is the distance from a side of the triangle to the incenter? can someone also explain how to get
denis23 [38]
In centre is the centre of a circle that is inscribed in a triangle, called the incircle, i.e. circle is tangent to all three sides AND located inside the triangle.  An incircle is roughly sketched in the accompanying diagram.

Since all radii of an incircle are equal, we have
4x-1=6x-5
Solving for x,
6x-4x=5-1
x=2
consequently, distance from incentre to each side of the triangle is
4(2)-1=7
check 6x-5=6(2)-5=7... checks.

Answers:
The value of x = 2
The distance from incentre to side of triangle is 7
5 0
3 years ago
Find the arc length of the semicircle. 7the grade
charle [14.2K]

so, is a semi-circle, half a circle, recall a circle has a total of 360°, so half of that will be 180°.

the diameter of that circle is 10, so its radius is half that, or 5.


\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =180\\ r=5 \end{cases}\implies s=\cfrac{(180)(\pi )(5)}{180}\implies s=5\pi \stackrel{\pi =3.14}{\implies s=15.7}

3 0
3 years ago
A relay team of 4 people runs 3 miles.If each person runs the same distance,How many miles does each person run?
Len [333]
Well first you have to divide 3 by 4, which is 0.75 or 3/4
6 0
3 years ago
Read 2 more answers
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