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ICE Princess25 [194]
3 years ago
6

Show work 9-17 please do

Mathematics
1 answer:
iragen [17]3 years ago
4 0
8, 5, 1, 12, 4 work shown in picture.

You might be interested in
Calculator
hodyreva [135]

Answer:

Step-by-step explanation:

x = 8

y = 40

6 0
3 years ago
If the probability of surviving a head on car accident at 55 mph is 0.097, then what is the probability of not surviving
BabaBlast [244]

The probability of not surviving a head-on car accident is: 0.903

Step-by-step explanation:

The probabilities of occurrence and non-occurrence of an event add up to one.

If p is the probability that an even will happen and q is the probability that it will not happen

Then

p+q=1

Here,

Probability of surviving = p = 0.097

Probability of not surviving = q = ?

0.097 + q = 1\\q = 1 - 0.097\\q = 0.903

The probability of not surviving a head-on car accident is: 0.903

Keywords: Probability, Inverse

Learn more about probability at:

  • brainly.com/question/4460262
  • brainly.com/question/4464845

#LearnwithBrainly

5 0
3 years ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
Pls pls help<br> Show work :)
Natasha2012 [34]

9514 1404 393

Answer:

  31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

  Sin = Opposite/Hypotenuse

  sin(30°) = BE/100

  BE = 100·sin(30°)

Then ...

  Tan = Opposite/Adjacent

  tan(58°) = BE/x

  x = BE/tan(58°) = 100·sin(30°)/tan(58°)

  x ≈ 31.243 . . . . units

_____

<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

5 0
3 years ago
Solve for x 10+ 4x -6 = -10
Anastasy [175]
I believe the answer is x = 3.5. may be wrong though
7 0
3 years ago
Read 2 more answers
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