The surface area of the composite figure is given by 730 sq.in
<h3>What are Composites ?</h3>
Composites are solid figures made up of basic shapes like rectangle , square and even of three dimensional figures like cube , cuboid etc.
It is given in the question to determine the area of the composite figure
Area of Cube is
Area = 6 * side²
Area = 6 * 4² = 96 sq.in
The surface area of the cuboid is equal to
Sum of surface area of all the sides
As the opposite sides are same
7x10x2 + 15x10x2 + 7x15x2
650 sq.in
As the surface area of the base of the cube is counted twice
Therefore it will subtracted from the total
96 + 650 - 4*4
=730 sq.in
Therefore the surface area of the composite figure is given by 730 sq.in
To know more about Composites
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I think just the "possible" ones, without fully factoring, are based on factors of the last whole number-- +20.
So factors of 20: 1, 2, 4, 5, 10, 20
It is a geometric mean sequence.
the 2nd term is 20, the 5th term is 0.16
so the next 3 terms are found by multiplying successive terms by the constant x. 20x^3 = 0.16 which is derived by multiplying 20 by x, three times to get 0.16
So x^3 =.008
x=0.2
The first term is found by saying a1^.2 = 20, so a1 = 100
When n = 1 2 3 4 5
t(n) = 100 , 20, 4, .8, .16
Answer:
Step-by-step explanation:
Given function is h(t) = -16t² + 1500
a). For h(t) = 1000 feet,
1000 = -16t² + 1500
1000 - 1500 = -16t² + 1500 - 1500
-500 = -16t²
t² = 
t = 
t = 5.59 sec
b). For h(t) = 940 feet,
940 = -16t² + 1500
940 - 1500 = -16t² + 1500 - 1500
-16t² = -560
t² = 
t = 
t = 5.92 sec
c). For domain and range of the function,
When the jumper comes down to the ground,
h = 0
0 =-16t² + 1500
t² = 
t = 
t = 9.68 sec
Since, x-values on the graph vary from x = 0 to x = 9.68,
Domain : [0, 9.68]
Vertex of the quadratic function: (0, 1500)
Since, coefficient of the highest degree term is negative, parabola will open downwards.
Therefore, y-values of the function will vary in the interval y = 0 to y = 1500
Range: [0, 1500]
Answer:
x = 5
x = 2
Step-by-step explanation:
2(2x + 4) = 8x - 12
2x + 4 = 4x - 6
x + 2 = 2x - 3
x = 5
Question 17
8/4 = (x + 2)/(2x - 2)
2(2x - 2) = x + 2
4x - 4 = x + 2
3x = 6
x = 2