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Oxana [17]
3 years ago
5

Need help please answer this question

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Remark

The key to this problem is finding the length of the hypotenuse of the 45o - 45o - 90o triangle. After than you can use the tangent to find x


Step One

Find the hypotenuse of the 45o - 45o - 90o right triangle

Use the fact that in this triangle, the two smaller sides of the triangle are equal.

They have a value of x. Since they are given as 12 we can solve for the hypotenuse.


Formula

a^2 + b^2 = c^2


Givens

a = 12

b = 12

c = ?


Sub and solve.

12^2 + 12^2 = c^2 Take out the common factor of 12^2

c^2 = 12^2 * (1 + 1)

c^2 = 2* 12^2 Take the square root of both sides.

sqrt(c^2) = sqrt(2 * 12^2)

sqrt(c^2) = sqrt(2) * sqrt(12^2)

sqrt(c) = 12 sqrt(2)


Step Two

Now use the 30 - 60 - 90 triangle to solve for x

The opposite side to the 60o angle is 12 sqrt(2)

Tan(60) = opposite / adjacent

Tan(60) = 12 sqrt(2) / adjacent


Tan(60) = sqrt(3)

adjacent = 12*sqrt(2)/sqrt(3)

Rationalize the denominator

adjacent = 12*sqrt(2) * sqrt(3) / (sqrt(3) * sqrt(3))

adjacent = 12*sqrt(6) / 3

adjacent = 4 sqrt(6)


Answer : D

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