Answer:
<em>The probability that the second ball is red is 71%</em>
Step-by-step explanation:
<u>Probabilities</u>
We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).
The first ball can be red (R) or green (G). The probability that it's red is computed by

The probability is's green is computed by

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

The total probability of the second ball being red is

The probability that the second ball is red is 71%
Answer:
t = 0
Step-by-step explanation:
(7t - 2) - (-3t + 1) = -3(1 - 3t)
because you can not do anything inside the parantheses, you distribute. there aren't any numbers on the left side of the parantheses on the left side of the equation so we just imagine the number 1. on the right side of the equation, just distribute normally
[ 1(7t - 2) -1(-3t + 1) = -3(1 - 3t) ]
will be
7t - 2 + 3t - 1 = -3 + 9t
add like terms
10t - 3 = -3 + 9t
subtract 9t from both sides
t - 3 = -3
add 3 to both sides
t = 0
A should be the right answer because 4*5/4=5 + 5*2=10 and 5+10=15.
Answer:
Step-by-step explanation:
m: y = -2x + 4
n: y = x - 1
l: y = 4
p: x = -4
Answer:
incorrect is They have a sum of -14