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DochEvi [55]
3 years ago
8

Find the first six terms of the sequence.

Mathematics
1 answer:
solong [7]3 years ago
4 0

a_1=-2\\\\a_n=3\cdot a_{n-1}\\-----------------------------------\\a_1=-2\\\\a_2=3\cdot a_{2-1}=3\cdot a_1\to a_2=3(-2)=-6\\\\a_3=3\cdot a_{3-1}=3\cdot a_2\to a_3=3(-6)=-18\\\\a_4=3\cdot a_{4-1}=3\cdot a_3\to a_4=3(-18)=-54\\\\a_5=3\cdot a_{5-1}=3\cdot a_4\to a_5=3(-54)=-162\\\\a_6=3\cdot a_{6-1}=3\cdot a_5\to a_6=3(-162)=-486\\\\Answer:\ \boxed{-2,\ -6,\ -18,\ -54,\ -162,\ -486}

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Answer:

Step-by-step explanation:

No

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Iteru [2.4K]

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If two lines are parallel then their slopes are equal.

We have the following line:

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Therefore a parallel line is of the form:

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8 0
3 years ago
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tatiyna

9514 1404 393

Answer:

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  c × (1 +40%) = m

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7 0
3 years ago
I need help, I don't know how to do it.
Sindrei [870]

Answer:

Step-by-step explanation:

to solve this problem we can use the Pythagorean theorem

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We have to find LU so we can proceed like this

x^2 + (x+1)^2 = LU^2

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LU = +/- \sqrt{2x^2+2x+1

we have to take only the positive value because a length can’t be negative.

2x^2 + 2x + 1 is positive for every value of x, so the final answer is

\sqrt{2x^2+2x+1}

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Vinvika [58]
49/9 because if you simplify it, it would be 7/3 which is equal to the original ratio.
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