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3 years ago

What is the value of x in the following system of equations? 11x + 12y = 13 14x + 15y = 16 A. x = −2 B. x = −1 C. x = 1 D. x = 2

1 answer:

5 0

11x + 12y = 13....multiply by 15
14x + 15y = 16...multiply by -12
---------------------
165x + 180y = 195 (result of multiplying by 15)
-168x - 180y = - 192 (result of multiplying by -12)
-------------------add
-3x = 3
x = -3/3
x = -1 <====

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Answer: There are several information's of immense importance already given in the question. Let us write them down first.

Diameter of the cylinder = 6 inches

Then

Radius of the cylinder = 3 inches.

Height of the cylinder = 3 * radius

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2 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

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