Question

On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = -16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is ________ feet

Answer 1

I believe its 144ft. Since 
h(2) = [-16(2^2) + 64(2) + 80] ft = 144 ft