Answer:12
Step-by-step explanation:
Let the numbers be a and b
a-3b=5 ........equation (1)
There product is :
ab=68 ..........equation (2)
From equation (1)
a-3b=5
Make a the subject of the formula
a=5+3b. ........equation (3)
Substitute equation (3) into equation (2)
(5+3b)b=68
3(b^2)+3b-68=0
The product is -204b^2(17 and -12)
(b+17)(b-12)=0
b=-17 or b=12
So the number is 12
Answer:
Help with what
Step-by-step explanation:
Answer:
-15
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
(4x + 2)(x - 5) / 2
x = 2
<u>Step 2: Evaluate</u>
- Substitute: (4 · 2 + 2)(2 - 5) / 2
- Parenthesis - Multiply: (8 + 2)(2 - 5) / 2
- Parenthesis - Add: 10(2 - 5) / 2
- Parenthesis - Subtract: 10(-3) / 2
- Multiply: -30 / 2
- Divide: -15
A squared +b squared= c squared
a squared+7 squared =10 squared
a squared + 49= 100
Then subtract 49 from 100 which is 51. Then your square root that number which is 7.14143