Answer:
70, 140, 280, 350
Step-by-step explanation:
Obviously, it must have the factors 2, 5, 7 as a minimum, so the smallest value is 2×5×7 = 70.
Any of these primes can be added to the product. In increasing order, the smallest additional factors will be 2, 4, 5, 7, 8, 10, ...
So, the four smallest numbers with prime factors of 2, 5, and 7 are ...
70 = 2·5·7
140 = 2²·5·7
280 = 2³·5·7
350 = 2·5²·7
Answer:
a) 6 mins
b) 70km/h
c) t= 45
Step-by-step explanation:
a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km
Duration
= 16 -10
= 6 minutes
b) Average speed
= total distance ÷ total time
Total time
= 24min
= (24÷60) hr
= 0.4 h
Average speed
= 28 ÷0.4
= 70 km/h
c) Average speed= total distance/ total time
Average speed
= 80km/h
= (80÷60) km/min
= 1⅓ km/min
1⅓= 28 ÷(t -24)
<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>
(t -24)= 28
t - 32= 28
t= 32 +28
t= 60
t= 
t= 45
*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.
Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)
To approximate the number of chairs that can be set up in floor space, we just have to divide the total floor area by the area that each chair needs. That is,
n = (40 ft x 32 ft) / (4 ft x 5 ft)
n = 64
Therefore, there are 64 chairs that can be set up in the floor.
If Samuel can type 40 words per minute, he can type
words in
minutes. So, the amount of minutes you're interested in is the solution of the equation
minutes.
Since 8750/60 is 145 with reminder 50, Samuel can type the required amount of words in 145 hours and 50 minutes.
The number (in scientific notation) is:

The power of "-4" tells us to move the decimal point 4 places to the left.
So, moving it, the number becomes: