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3 years ago

PT = 7x + 3 and TQ = 9x - 5

Mathematics

1 answer:

3241004551 [841]3 years ago

3 0

Answer:

Solution for 7x-3=9x+5 equation:

x = -4

Step-by-step explanation:

Simplifying

7x + -3 = 9x + 5

Reorder the terms:

-3 + 7x = 9x + 5

Reorder the terms:

-3 + 7x = 5 + 9x

Solving

-3 + 7x = 5 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.

-3 + 7x + -9x = 5 + 9x + -9x

Combine like terms: 7x + -9x = -2x

-3 + -2x = 5 + 9x + -9x

Combine like terms: 9x + -9x = 0

-3 + -2x = 5 + 0

-3 + -2x = 5

Add '3' to each side of the equation.

-3 + 3 + -2x = 5 + 3

Combine like terms: -3 + 3 = 0

0 + -2x = 5 + 3

-2x = 5 + 3

Combine like terms: 5 + 3 = 8

-2x = 8

Divide each side by '-2'.

x = -4

Simplifying

x = -4

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aivan3 [116]

Answer:

Step-by-step explanation:

C: Side-Angle-Side

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3 years ago

What is the percent between 4 and 3.80

crimeas [40]

0.20 so %20 because there is 20 100ths between that

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2 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

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3 years ago

What is the original price if there is a 45% discount and the sale price is $550?

Svetradugi [14.3K]

Original price×(1-discount price)=new price or sale price so

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So the original price is 1000

3 0

2 years ago

Sixty percent of the students at a certain school wear neither a ring nor a necklace. Twenty percent wear a ring and 30 percent

Reptile [31]

Answer:

0.4

Step-by-step explanation:

Given

60 % wear neither ring nor a necklace

20 % wear a ring

30 % wear necklace

This question can be Solved by using Venn diagram

If one person is choosen randomly among the given student the probability that this student is wearing a ring or necklace is

$P\left ( wear \ ring\ or \ necklace )+P\left ( neither\ ring\ or\ necklace)=1$

$P\left ( wear \ ring\ or\ necklace )=1-0.6=0.4$

The sum of probabilty is equal to 1 because it completes the set

Therefore the required probabilty is 0.4

7 0

2 years ago