Answer:
99% Confidence interval: (1196,1973)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 20
Mean, μ = 1584
Standard Deviation, σ = 607
99% Confidence interval:
Putting the values, we get,
Thus, there is a 99% chance that it will break in approximately 1196 to 1972
For question a there would be 200 terms because the exponent only rises by 1 each time, but there is also a 1 at the beginning so it would be 199+1.
For question b, you divide 312 by 4 which would give you 78 terms. This is because the ending term is 319 and the starting term is 7, but since it didn’t start at 1, you had to subtract 319 from 7 to get 312, and then divide 312 by 4, because each term rises by 4.
For question c, you subtract 533 from 33, which would give you 500 terms. This is because it didn’t start at 0, so you have to subtract from the term it started on, which was 33.
I hope this helped.
Answer:
what?////
Step-by-step explanation:
Answer:
467,059,500
Thank you for the points! And this is really easy, just add :))
8x-8x+6=14
so this answer is no solution