Answer:
f(x)=-18x^2
Step-by-step explanation:
Given:
1+Integral(f(t)/t^6, t=a..x)=6x^-3
Let's get rid of integral by differentiating both sides.
Using fundamental of calculus and power rule(integration):
0+f(x)/x^6=-18x^-4
Additive Identity property applied:
f(x)/x^6=-18x^-4
Multiply both sides by x^6:
f(x)=-18x^-4×x^6
Power rule (exponents) applied"
f(x)=-18x^2
Check:
1+Integral(-18t^2/t^6, t=a..x)=6x^-3
1+Integral(-18t^-4, t=a..x)=6x^-3
1+(-18t^-3/-3, t=a..x)=6x^-3
1+(6t^-3, t=a..x)=6x^-3
That looks great since those powers are the same on both side after integration.
Plug in limits:
1+(6x^-3-6a^-3)=6x^-3
We need 1-6a^-3=0 so that the equation holds true for all x.
Subtract 1 on both sides:
-6a^-3=-1
Divide both sides by-6:
a^-3=1/6
Raise both sides to -1/3 power:
a=(1/6)^(-1/3)
Negative exponent just refers to reciprocal of our base:
a=6^(1/3)
820.681 in expanded form would look like this:
Answer:
The equation of the line would be y = 5x - 28
Step-by-step explanation:
First, we need to know that perpendicular lines have opposite and reciprocal slopes. Give that information, we know that the new line will be the reciprocal and opposite of -1/5. This would be 5. Now that we have that information, we can use it along with a point to fill in the point-slope form of the equation.
y - y1 = m(x - x1)
y - 2 = 5(x - 6)
Then we must solve for y.
y - 2 = 5(x - 6)
y - 2 = 5x - 30
y = 5x - 28
Answer:
7x^2+5x
Step-by-step explanation:
Given
Polynomial 1: 9x^2+8x
Polynomial 2: 2x^2+3x
We have to find subtraction of both
So,
9x^2+8x - (2x^2+3x)
First of all the brackets will be eliminated by multilying the minus sign
9x^2+8x-2x^2-3x
The terms with same power of variable will be written together
9x^2-2x^2+8x-3x
=7x^2+5x ..
Answer:
Step-by-step explanation:8 inches
89 is the answe 89
