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hichkok12 [17]
3 years ago
5

Describe the process for calculating the volume of a pyramid. Use complete sentences.

Mathematics
1 answer:
Georgia [21]3 years ago
8 0
For the answer to the question above, this question is incomplete. I've answered this question before.
Is it like this?
V = (1/3) * (area of the base) * height 

<span>If you have a pyramid with a square base, you just multiply the length of both sides together. For example, if the pyramid was 9 inches on a side, the area of the base is 9 * 9 = 81 sq. inches. </span>

<span>Then you multiply that by the height and finally take 1/3 of the result. For example, if the pyramid was 10 inches high, you multiply 81 sq. inches x 10 inches = 810 cubic inches. But you have to remember to take a third of that result. 810 cubic inches / 3 = 270 cubic inches.
</span>I hope this helps
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3 years ago
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3 years ago
A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
2 (3*5) divided 2 to the secound power + 1
Levart [38]

Answer 6

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3 years ago
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