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SCORPION-xisa [38]
3 years ago
7

Need help on this please giving brainlest! :)​

Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Answer:

a) (-4, 5)

b) (4, -5)

Step-by-step explanation:

Just reverse the signs or use desmos as a better example.

Assoli18 [71]3 years ago
5 0

Answer:(4,-5) and (-4,5)

Step-by-step explanation: anything reflected from the x or y axis is the postive version which is  -4 has an absolute value of 4

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33/7 + 28/6 needs to made to a mixed number but how?
gayaneshka [121]

Answer:

Step-by-step explanation:

33/7 = 4 5/7

4*7= 28

5 is left.

So it would be 5/7 plus the 4.

28/6 = 4 4/6

4 4/6 + 4 5/7=

4 27/42 + 4 30/42= 4 57/42

4 57/42= 4 15/42 or 4 5/14

6 0
3 years ago
Help asap??!!?!?!.....................................!
Klio2033 [76]
8x8/7 answer true butty they’re
6 0
2 years ago
A tax cabs entry cost is $2.50 in each mile traveled is $.75 . Write an expression for the total cost of the taxi ride traveling
lara31 [8.8K]
2.50+.75x
hope it helps and plz mark this brainliest!!
4 0
3 years ago
Read 2 more answers
I need help does anyone know?
Nuetrik [128]

Answer:

$19.6

Step-by-step explanation:

He bought 6 video games and 1 dvd

We know that each video game costs $2.7 and each dvd costs 3.4

To get the sum = v x 6 + d x 1

= 2.7 x 6 + 3.4 x 1

= 16.2 + 3.4

= $19.6

4 0
3 years ago
Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian
777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\B=30^o

Applying the law of sines

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(A)}=\frac{2}{sin(30^o)}

sin(A)=1

so

A=90^o

Find the measure of angle C

In a right triangle

we know that

B+C=90^o ----> by complementary angles

B=30^o

therefore

C=60^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{b}{sin(B)}

substitute the given values

\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}

c=2\sqrt{3}\ units

therefore

The dimensions of the triangle are

A=90^o

B=30^o

C=60^o

a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units

<em>Second case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\A=30^o

Applying the law of sines

Find the measure of angle B

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(30^o)}=\frac{2}{sin(B)}

sin(B)=0.25

so

using a calculator

B=14.48^o

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

A=30^o\\B=14.48^o

therefore

30^o+14.48^o+C=180^o

C=135.52^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}

c=5.61\ units

therefore

The dimensions of the triangle are

A=30^o

B=14.48^o

C=135.52^o

a=4\ units\\b=2\ units\\c=5.61\ units

see the attached figure to better understand the problem

4 0
3 years ago
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