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Elan Coil [88]
3 years ago
13

Suppose that you toss a rock upward so that it rises and then falls back to the earth. If the acceleration due to gravity is 9.8

m/sec2, what is the rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero)? Assume that air resistance is negligible.
Physics
1 answer:
telo118 [61]3 years ago
4 0

The Rock's acceleration is 9.8 m/s^2 from the moment it leaves your hand until the moment it hits the ground. Its acceleration never changes. That's the acceleration of gravity as long as nothing is pushing the rock or holding it back.

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What type of energy does gasoline have? How could you relate it to the movement of a vehicle that uses it?
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Answer:

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3 years ago
A steel drill making 180 rpm is used to drill a hole in a block of steel. The mass of the steel block and the drill is 180 g. If
SVETLANKA909090 [29]

Answer:

a) 37.8 W

b) 2 Nm

Explanation:

180 g = 0.18 kg

We can also convert 180 revolution per minute to standard angular velocity unit knowing that each revolution is 2π and 1 minute equals to 60 seconds

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We can use the heat specific equation to find the rate of heat exchange of the steel drill and block:

\dot{E} = mc\Delta \dot{t} = 0.18*420*0.5 = 37.8 J/s

Since the entire mechanical work is used up in producing heat, we can conclude that the rate of work is also 37.8 J/s, or 37.8 W

The torque T required to drill can be calculated using the work equation

E = T\theta

\dot{E} = T\dot{\theta} = T\omega

T = \frac{\dot{E}}{\omega} = \frac{37.8}{18.85} = 2 Nm

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The spacing and distribution of individuals within a population is known as
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Answer:

Species distribution

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