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Gekata [30.6K]
4 years ago
12

The eiffel tower is a steel structure whose height increases by 19.5 cm when the temperature changes from −8 to +42 °c. what is

the approximate height (in meters) at the lower temperature? m
Physics
1 answer:
Readme [11.4K]4 years ago
6 0
 The coefficient of expansion is 13 * 10^-6 m per meter length.per oK 
The temperature difference = 42 - - 8 = 50 oC 
delta T = (42 + 273) - (-8 + 273) = 50 oK 
delta L = L * 13* 10^6 m/oK 
oK = 50 oK delta L = 19.5 cm = 19.5 cm [1m / 100 cm] = 0.195m 
So we need to find the length and it is computed by:
0.195= L * 13 * 10^-6 * 50 L = 0.195 / (13*10^-6*50) L = 300 m 
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A cement factory emits 900 kilograms of CO2 to produce 1,000 kilograms of cement. A fully grown tree removes six kilograms of CO
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Since the factory will be producing 100,000 kilograms of cement, using the relation 1000 kg of cement = 900 kg of CO2, then the factory will be emitting 90,000 kg of CO2 at the same time. To counteract the emission, a tree can remove 6 kg of CO2 per day. Dividing 90,000 kg by 6 kg to know the number of trees, we need 15000 trees to counter the emission. Since 1 acre of land holds 200 trees, we need 75 acres of land to hold the 15000 trees.
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4 years ago
Three Carnot engines operate between the following temperature limits.
Kipish [7]

Answer:c>a>b

Explanation:

Given

All the engine extracts same amount of heat(Q) from High-temperature reservoir

For a) 400 and 500 K

\eta _{engine}=1-\frac{T_L}{T_H}

\eta _{engine}=\frac{work\ supplied}{heat\ supplied}

1-\frac{400}{500}=\frac{W_a}{Q}

W_a=\frac{Q}{5}

For b)500 K and 600K

1-\frac{500}{600}=\frac{W_b}{Q}

W-b=\frac{Q}{6}

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6 0
4 years ago
Suppose that the moment of inertia of a skater with arms out and one leg extended is 3.5 kg⋅m2 and for arms and legs in is 0.80
sergiy2304 [10]

Answer:

1.3  rev/s

Explanation:

I_{o} = Moment of inertia when arms and one leg of the skater is out = 3.5 kgm²

I_{i} = Moment of inertia when arms and  legs of the skater are in = 0.80 kgm²

w_{i} = Angular speed of skater when arms and  legs of the skater are in = 5.5 rev/s

w_{o} = Angular speed of skater when arms and  legs of the skater are out = ?

Using conservation of angular momentum

I_{i} w_{i} = I_{o} w_{o}

(0.80) (5.5) = (3.5) w_{o}

w_{o} = 1.3 rev/s

8 0
3 years ago
The hypotenuse of a right triangle is 29.0 centimeters. The length of one of its legs is 20.0 centimeters. What is the length of
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C2 = a2 + b2
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841 = a^2 + 400
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a = 21

3 0
4 years ago
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