Answer:
a = 4
b = 11
Step-by-step explanation:
To convert the recurring decimals into fraction we will follow the following process.
Given recurring decimal is 0.36363636....
Let x = 0.363636......... (1)
Multiply this decimal with 100.
100x = 36.36363636...........(2)
Now subtract expression (1) from expression (2)
100x = 36.363636.......
<u> x = 0.363636.......</u>
99x = 36
x = 
x = 
Since, 
a = 4 and b = 11 will be the answer.
Answer:
it will take a programmer about 16.67 times to work before they are fired
Step-by-step explanation:
From the information given;
The transistion matrix for this study can be computed as:
P M X
P 0.7 0.2 0.1
M 0 0.95 0.05
X 0 0 1
where;
The probability that the programmer remains a programmer = 
The probability that the programmer turns out to be a manager = 
The probability that the programmer is being fired = 
Thus, the required number of years prior to the moment being fired for an employee y(P), for programmer and y(M) for manager is represented by ;



y(M) = 
y(M) =20
y(P)=1+0.7y(P)+0.2y(M)
y(P) - 0.7y(P) = 1 + 0.2y(M)
0.3y(P) = 1 + 0.2(20)=1+4
0.3y(P) = 1 + 4
0.3y(P) = 5


Therefore, it will take a programmer about 16.67 times to work before they are fired
Answer:
Step-by-step explanation:
P(D/M₁) = .04 ( probability of defect from a 1 st machine )
P(D/M₂) = .06
P(D/M₃) = .01
P( M₁ )= .3 ( probability of manufacture from 1 st machine )
P(M₂) = .2
P(M₃)= .5
P( M₁/D) ( Probability of manufacture from 1 st machine , given it is defective )
= P( M₁ )xP(D/M₁) / [P( M₁ )xP(D/M₁) +P( M₂ )xP(D/M₂)+P( M₃ )xP(D/M₃)]
= .3 x .06 / .3 x .06 + .2 x .06 + .5 x .01
= .018 / .035
= 18/35
Answer:
A is right
B is acute
C is obtuse
D is right
Step-by-step explanation:
90 is right
anything under 90 is acute
over 90 obtuse