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2 years ago

A car dealership is advertising a car for $16,299.99. If the sales tax rate is 6.5 percent, what

Mathematics

1 answer:

Alex777 [14]2 years ago

4 0

Answer:

C. 1059.50

Step-by-step explanation:

Sales price x sales tax rate = sales tax

16299.99 x .065 (6.5%) = 1059.50

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The Star television costs $750 more than the Jupiter television. The two models cost $2,600 all together. Sandra writes an equat

tiny-mole [99]

2600 - 750 = 1850 , 1850 / 2 = 925 , 925 + 750 = 1675 . star = $1675 and jupiter = $925 . so 2600 - c = star price ($1675)

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3 years ago

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GUYS I SWEARRR I NEED HELP PLS IM BEGGING IMA FAIL MA TEST

liubo4ka [24]

Answer:

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3 years ago

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HELPP!!!! 100 points. Which expression is equivalent

devlian [24]

Answer:

$\Large \boxed{\sf A}$

Step-by-step explanation:

$\displaystyle 2x\sqrt{44x}-2\sqrt{11x^3}$

Let<em> x</em> = 2 because x > 0

$\displaystyle 2(2)\sqrt{44(2)}-2\sqrt{11(2)^3}=4\sqrt{22}$

See which expression is equal to 4√22 when <em>x</em> = 2

$2(2)\sqrt{11(2)}=4\sqrt{22}$

The expression is option A

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2 years ago

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The directions are with the pic below. I have to send a 2nd pic. Couldn’t fit everything on the page

Nonamiya [84]

If the pentagon is rotated 360° about the origin, that means the new figure will be exactly in the same position as the original image, because a rotation of 360° about the origin doesn't change the figure position or orientation.

So, if the vertex was located at (10, -8), the new figure will also have a vertex located at (10, -8).

Therefore the correct option is the fourth one.

4 0

10 months ago

Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

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1 year ago