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3 years ago

Please help fasttttttt

Mathematics

1 answer:

lord [1]3 years ago

3 0

Answer:

40 or 50 i cant see, is it closer in size to L or I

Step-by-step explanation:

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HELP ITS A TEST- Question is in the photo

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

i simply put the answer in desmos a graphing calculator and compared them hope this helps

7 0

3 years ago

Read 2 more answers

Please help thank you.

Brilliant_brown [7]

Question 1:
For that point where all the lines intersect to be an incenter, the following must be true
4x - 1 = 6x - 5
Subtract both sides by 6x
-2x -1 = -5
Add both sides by 1
-2x = -4
Divide both sides by -2
x= 2

Question 2:
Plug in x=2 into any of the two equations.

You get 7.

Have an awesome day! :)

5 0

3 years ago

Mr. Jones must pay his electric bill and his phone bill each month he also pays for one round of miniature golf and a monthly ci

Natalka [10]

B

the other options all have a set price, the answers in b could all change price from month to month

7 0

3 years ago

Help please 17 points!!

Darina [25.2K]

Answer:

I dont really do this kind of work but i think its A

Step-by-step explanation:

3 0

3 years ago

The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou

Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as $\sigma^2 = mean = 6.2$

hence, standard deviation is given as $\sqrt{6.2} = 2.48998$

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is

$P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)$

$= \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}$

= 0.002029 + 0.012582+ 0.039006

= 0.053617

= 0.0536

7 0

3 years ago