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3 years ago

Please help fasttttttt

Mathematics

1 answer:

lord [1]3 years ago

3 0

Answer:

40 or 50 i cant see, is it closer in size to L or I

Step-by-step explanation:

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What transformations were applied to the graph of the parent function y=tan(x) to produce the function graphed below?

xxMikexx [17]

Answer:

It's D.

Step-by-step explanation:

The graph of tan x passes through (0,0) whereas this graph passes through the point (pi/4 , 0) so it a horizontal translation to the right. We see that the period is 6 units along the x axis which is 6 * pi/4 = 3 pi/2.

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3 years ago

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The coordinates of the vertices of a right triangle are (0, 0), (5, 0) and (0, 3). Which of the following statements is true?

Sphinxa [80]

I think A I'm not sure.

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3 years ago

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Can someone help me!!!

Eva8 [605]

$\text {Distance} = \sqrt{(7-0)^2 + (-6+3)^2} = \sqrt{7^2+(-3)^2} = \sqrt{58} = 7.6 \text{ units}$

Answer: 7.6 units

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3 years ago

I need help with this question:

Zolol [24]

Answer:

a) #4 vertical angles are congruent

b) # 1 ∠3 ≅ ∠7

c) # 6 Transitive property

Step-by-step explanation:

a. Vertical angles - opposite angles that are equal.

b. corresponding angles - in the same place but on different parallel lines

and are equal.

c. a = b, b = c so a = c

5 0

2 years ago

I need help please help me thanks please

Vitek1552 [10]

so we have a table of values, with x,y coordinates, so let's use any two of those points to get the slope of the table and use the point-slope form to get its equation

$~\hspace{2.7em}\stackrel{\textit{let's use}}{\downarrow }\qquad \stackrel{\textit{and this}}{\downarrow }\\\begin{array}{|lr|r|r|r|r|}\cline{1-6}x&0&1&2&3&4\\y&-1&3&7&11&15\\\cline{1-6}\end{array}\\\\[-0.35em]\rule{34em}{0.25pt}\\\\(\stackrel{x_1}{1}~,~\stackrel{y_1}{3})\qquad(\stackrel{x_2}{4}~,~\stackrel{y_2}{15})$

$\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{15}-\stackrel{y1}{3}}}{\underset{run}{\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{12}{3}\implies 4\\\\\\% point-slope intercept\begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\\\cline{1-1}\\y-y_1=m(x-x_1)\\\\\cline{1-1}\end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{4}(x-\stackrel{x_1}{1})\\\\\\y-3=4x-4\implies y = 4x-1\implies \blacktriangleright y = 4x+(-1)\blacktriangleleft$

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3 years ago